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5x + 5x+1 = 150
⇒ 5x + 5x .5 = 150
⇒ 5x .(5 + 1) = 150
⇒ 5x = 150 ÷ 6
⇒ 5x = 25
⇒ 5x = 52
⇒ [ x = 2 = −2 V ậy [ x = 2 = −2
\(5^x+5^{x+1}=150\)
\(\Rightarrow5^x+5^x.5=150\)
\(\Rightarrow5^x.\left(5+1\right)=150\)
\(\Rightarrow5^x=150\div6\)
\(\Rightarrow5^x=25\)
\(\Rightarrow5^x=5^2\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)
\(Vậy\) \(\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)
\(5^x+5^{x+1}=150\)
⇒ \(5^x.1+5^x.5=150\)
⇒ \(5^x.\left(1+5\right)=150\)
⇒ \(5^x.6=150\)
⇒ \(5^x=150:6\)
⇒ \(5^x=25\)
⇒ \(5^x=5^2\)
⇒ \(x=2\)
Vậy \(x=2.\)
Chúc bạn học tốt!
a)|x|=\(\frac{1}{5}\)
\(\Rightarrow x=\frac{1}{5}hoặcx=\frac{-1}{5}\)
b)\(x:\left(\frac{-1}{2}\right)^3=\frac{-1}{2}\)
\(x:\frac{-1}{8}=\frac{-1}{2}\)
\(x=\frac{-1}{2}\times\frac{-1}{8}\)
\(x=\frac{1}{16}\)
c)\(\frac{2}{3}+\frac{5}{3}x=\frac{5}{7}\)
\(\frac{5}{3}x=\frac{5}{7}-\frac{2}{3}\)
\(\frac{5}{3}x=\frac{15}{21}-\frac{14}{21}\)
\(\frac{5}{3}x=\frac{1}{21}\)
\(x=\frac{1}{21}:\frac{5}{3}\)
\(x=\frac{1}{21}\times\frac{3}{5}\)
\(x=\frac{1}{35}\)
d)\(\frac{x}{10}=\frac{12}{5}\)
\(\frac{x}{10}=\frac{24}{10}\)
\(\Rightarrow x=24\)
tjck mjnh nhen
1) \(\frac{x-1}{x-5}=\frac{6}{7};\left(x-1\right).7=\left(x-5\right).6\)
7x - 7 = 6x - 30
=> 7x - 6x = -30 - (-7)
x = -23
2) \(\frac{x-1}{3}=\frac{x+3}{5};\left(x-1\right).5=\left(x+3\right).3\)
5x - 5 = 3x + 9
=> 5x - 3x = 9 - (-5)
2x = 14
x = 7
3) \(\frac{3}{7}=\frac{2x+1}{3x+5};\left(3x+5\right).3=\left(2x+1\right).7\)
9x + 15 = 14x + 7
9x - 14x = 7-15
5x = -8
x = -8/5
1) =>\(\hept{\begin{cases}x-1=6\\x-5=7\end{cases}=>\hept{\begin{cases}x=6+1=7\\x=7+5=13\end{cases}}}\)
Vậy x\(\varepsilon\){7;13}
2)
5^x + 5^x + 1 = 150
=> 5^x . ( 1 + 5 ) = 150
=> 5^x . 6 = 150
=> 5^X = 150 : 6
=> 5^x = 25
=> 5^x = 5^2
=> x = 2
\(5^x+5^{x+1}=150\)
\(\Rightarrow5^x+5^x.5=150\)
\(\Rightarrow5^x\left(5+1\right)=150\)
\(\Rightarrow5^x=150:6\)
\(\Rightarrow5^x=25\)
\(\Rightarrow\orbr{\begin{cases}x=2\\x=-2\end{cases}}\)