Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
=\(\frac{1}{2}x\frac{2}{3}x...x\frac{2017}{2018}\)
=\(\frac{1}{2018}\)
bạn trừ ra là đc
\(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot....\cdot\left(1-\frac{1}{2017}\right)\cdot\left(1-\frac{1}{2018}\right)\)
\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot...\cdot\frac{2016}{2017}\cdot\frac{2017}{2018}\)
\(=\frac{1\cdot2\cdot3\cdot....\cdot2016\cdot2017}{2\cdot3\cdot4\cdot....\cdot2017\cdot2018}\)
\(=\frac{1}{2018}\)
\(=\left(\frac{1}{2}\right).\left(\frac{2}{3}\right).\left(\frac{3}{4}\right)....\left(\frac{2017}{2018}\right)\)
\(=\frac{1.2.3....2017}{2.3.4...2018}\)
\(=\frac{1}{2018}\)
\(=\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot...\cdot\left(1-\frac{1}{2018}\right)\)
\(=\frac{1}{2}\cdot\frac{2}{3}\cdot...\cdot\frac{2017}{2018}\)
\(=\frac{1}{2018}\)
Tìm x biết:
a) (15 × 19 – x – 0,15):0,25 = 15 : 0,25
b)\(2\frac{2}{3}-x=\frac{1}{3}\cdot\frac{6}{2}\)
a) (15 x 19 - x - 0,15) : 0,25 = 15 : 0,15
(285 - x - 0,15) : 0,25 = 60
(285 - x - 0,25) = 60 : 0,25
( 285 - x - 0,25) = 15
285 - x = 15 + 0,25
285 - x = 15,25
x = 285 - 15,25
x = 269,75
a) \(x\cdot\frac{1}{2}+x\cdot\frac{1}{4}+x\cdot\frac{1}{8}=\frac{21}{24}\)
\(x\cdot\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\right)=\frac{7}{8}\)
\(x\cdot\frac{7}{8}=\frac{7}{8}\)
\(\Rightarrow x=\frac{7}{8}\div\frac{7}{8}=1\)
b) \(\left(x+4\right)+\left(x+9\right)+\left(x+14\right)+.....+\left(x+44\right)+\left(x+49\right)=1430\)
\(\left(x+x+x+....+x+x\right)+\left(4+9+14+...+44+49\right)=1430\)
\(10x+265=1430\)
\(10x=1430-265\)
\(10x=1165\)
\(\Rightarrow x=\frac{1165}{10}=116,5\)
c) \(x\cdot0,25-0,5=1\)
\(x\cdot0,25=1+0,5\)
\(x\cdot0,25=1,5\)
\(\Rightarrow x=1,5\div0,25=6\)
\(17\cdot\frac{3}{4}-17\cdot0,25+17\cdot\frac{1}{2}\)
\(=17\cdot0,75-17\cdot0,25+17\cdot0,5\)
\(=17\cdot\left(0,75-0,25+0,5\right)\)
\(=17\cdot1\)
\(=17\)
\(17\times\frac{3}{4}-17\times0,25+17\times\frac{1}{2}\)\(=17\times\frac{3}{4}-17\times\frac{1}{4}+17\times\frac{1}{2}\)\(=17\times\left(\frac{3}{4}-\frac{1}{4}+\frac{1}{2}\right)\)
\(=17\times\left(1\right)\)\(=17\)
\(4:x+x.2=7\)
\(\frac{1}{4}x+x.2=7\)
\(\frac{x.9}{4}=7\)
\(x=7:\frac{9}{4}=7.\frac{4}{9}=\frac{28}{9}\)
50%=1/2
0,25=1/4
50% *x + 3/4 * x + 0,25 * x - 1/2 * x = 2018
=> (1/2 + 3/4 + 1/4 - 1/2)* x = 2018
=> 1 * x = 2018
=> x = 2018
\(50\%\cdot x+\frac{3}{4}\cdot x+0,25-x+\frac{1}{2}\cdot x=2018\)
\(\Leftrightarrow0,5x+\frac{3}{4}x+0,25x+\frac{1}{2}x=2018\)
\(\Leftrightarrow x\left(0,5+\frac{3}{4}+0,25+\frac{1}{2}\right)=2018\)
\(\Leftrightarrow1,75x=2018\)
\(\Leftrightarrow x=...\)
HỌC TỐT!
Cơ mà "Toán lớp 5"????