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a, 10 . 27 - 27 : 9
= 270 - 3
= 263
b, 72 . 33 + 72 . 67
= 72 ( 33 + 67 )
= 72 . 100
= 49 . 100
= 4900
c, 490 - [ ( 128 + 22 ) : 3 . 22 ] - 7
= 490 - ( 150 : 3 . 4 ) - 7
= 490 - ( 50 . 4 ) - 7
= 490 - 200 - 7
= 290 - 7
= 283
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a, 125+70+375+230
= (125+375)+(70+230)
= 500+300 = 800
b, 7 2 . 33 + 7 2 . 67
= 49.33+49.67 = 49.(33+67) = 49.100 = 4900
c, 35.11+65.18+35.13+65.6
= 35.(11+13)+65.(18+6) = 35.24+65.24 = 24.(35+65) = 24.100 = 2400
d, 490 – {[(128+22):3. 2 2 ] – 7}
= 490 – {[150:3.4] – 7}
= 490 – {[50.4] – 7}
= 490 – {200 – 7}
= 490 – 193 = 297
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\(D=\) \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right).2}\)
\(=\) \(\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}\)
\(=\) \(\frac{11.3^{29}-3^{30}}{4.3^{28}}\)
\(=\) \(\frac{11.3^{29}-3^{29}.3}{4.3^{28}}\)
\(=\) \(\frac{3^{29}\left(11-3\right)}{3^{28}.4}\)
\(=\) \(\frac{3^{28}.3.8}{3^{28}.4}\)
\(=\) \(\frac{3^{28}.3.4.2}{3^{28}.4}\)
\(=\) \(6\)
Chúc bn hok tốt ~
\(D=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right).2}\)
\(=\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}\)
\(=\frac{11.3^{29}-3^{30}}{4.3^{28}}\)
\(=\frac{11.3^{29}-3^{29}.3}{4.3^{28}}\)
\(=\frac{3^{29}\left(11-3\right)}{3^{28}.4}\)
\(=\frac{3^{28}.3.8}{3^{28}.4}\)
\(=\frac{3^{28}.3.4.2}{3^{28}.4}=6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1. 53 = 5.5.5 = 125
2. 27 = 2.2.2.2.2.2.2 = 128
3. 44 = 4.4.4.4 = 256
4. 73 = 7.7.7 = 343
6. 35 = 243
7. 26 = 64
8. 34 = 81
9. 83 = 512
11. 132 = 169
12. 112 = 121
13. 142 = 196
14. 152 = 225
16. 172 = 289
17. 182 = 324
18. 192 = 361
19. 202 = 400
21. 104 = 10000
22. 105 = 100000
23. 106 = 1000000
24. 107 = 10000000
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a,( 393+390) : (317. 373)
= (33+1). 390 : 390
= 33+1
=27+1
=28
b,(556+57) : (549+1)
=57. (549+1) : (549+1)
=57= 78125
c,(722+721+720) ; (25+24+32)
= 720. (72+71+1) : [24. (2+1)+32 ]
= 720. 57 : [ 24. 3 +32 ]
= 720. 57 : ( 24+3) . 3
= 720. 57 : 19 . 3
= 720. 57 : 57
= 720
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![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : \(A=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(\Rightarrow\) \(A=\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}\)
\(\Rightarrow\) \(A=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=\frac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=\frac{3^{29}.8}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=\frac{3^{29}.2^3}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=3.2\)
\(\Rightarrow\) \(A=6\)
Vậy A = 6
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