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(x+1)+(x+2)+(x+3)=4x
x+1+x+2+x+3=4x
(x+x+x)+(1+2+3)=4x
x*3+6=4x
6=1*x(bớt cả hai vế đi 3*x)
x=6/1(Tìm thừa số)
x=6
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với |2x+10|+|3x-1|+|1-x|=3 ta có 2 trường hợp:
trường hợp 1:|2x+10|+|3x-1|+|1-x|=2x+10+3x-1+1-x=3
4x+10=3
4x=-7
x=-7/4
trường hợp 2:|2x+10|+|3x-1|+|1-x|=-(2x+10)+[-(3x-1)]+[-(1-x)]=3
-2x-10-3x+1-1+x=3
-4x-10=3
-4x=13
x=-13/4
/ là dấu phần nhé!
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\(-\frac{1}{7}+\frac{5}{3}+\frac{5}{4}+\frac{1}{3}-\frac{3}{2}\)
\(=\left(-\frac{1}{7}+\frac{5}{3}-\frac{3}{2}\right)+\left(\frac{5}{3}+\frac{1}{3}\right)\)
\(=\frac{-6}{42}+\frac{70}{42}-\frac{63}{42}+\frac{6}{3}\)
\(=\frac{-6+70-63}{42}+2\)
\(=\frac{1}{42}+\frac{84}{42}\)
\(=\frac{85}{42}\)
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\(-2x+3.\left\{12-2.\left[3x-\left(20+2x\right)-4x+1\right]\right\}=45\)
\(\Leftrightarrow-2x+3.\left\{12-2\left[3x-20-2x-4x+1\right]\right\}=45\)
\(\Leftrightarrow-2x+3.\left\{12-2.\left[-3x-19\right]\right\}=45\)
\(\Leftrightarrow-2x+3.\left\{12+6x+38\right\}=45\)
\(\Leftrightarrow-2x+36+18x+114=45\)
\(\Leftrightarrow16x+150=45\Leftrightarrow16x=-105\Leftrightarrow x=\frac{-105}{16}\)
mình giúp rùi đó nhớ k mk nhé ....
= -2x + 3[12-2(3x-20-2x-4x+1)]=45
= -2x +3[12-2(-3x-19)]=45
= -2x+3(12+6x+38)=45
= -2x+3(6x+50)=45
=-2x+18x+150=45
=16x=-105
=>x=-105/16
b) x= 808