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a) | x + 10 | - ( 5 - 3x ) = ( 4x - 10 ) - ( x - 5 )
=> | x + 10 | = ( 5 - 3x ) + ( 4x - 10 ) - ( x - 5 )
=> | x + 10 | = 5 - 3x + 4x - 10 - x + 5
=> | x +10 | = 0
=> x + 10 = 0
=> x = -10
Vậy...
b) Làm tương tự
Kết quả : | 3x + 21 | = -10 ( vô lí) ( vì |3x+21| >= 0 mà -10<0)
Vậy không tìm được x thỏa mãn bài toán
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\(\frac{x}{3}+3x-10=10\)
\(\frac{x}{3}+\frac{9x}{3}=10+10=20\)
\(\frac{10x}{3}=20\)
\(10x=20.3=60\)
\(x=\frac{60}{10}=6\)
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10(x-20)=10
x - 20 = 10-10
x - 20 = 0
x = 0 + 20
x = 20
597 - 3x = 9.2
597 -3x = 18
3x = 597 - 18
3x = 579
x = 579 : 3
x = 193
10 + 2x = 1024 : 64
10 + 2x = 16
2x = 16 - 10
2x = 6
x = 6 : 2
x = 3
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\(10\left(18-3x:9\right)=10\)
\(18-3x:9=1\)
\(3x:9=17\)
\(3x=153\)
\(x=51\)
vay \(x=51\)
18-3x:9=10:10
18-3x:9=1
18-3x=9x1
18-3x=9
3x=18-9
3x=9
x=9:3
x=3
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Trl:
\(\left(3x-2^4\right).7^{10}=2.7^{10}\)
\(\Rightarrow\left(3x-16\right)=2.7^{10}:7^{10}\)
\(\Rightarrow\left(3x-16\right)=2.1\)
\(\Rightarrow\left(3x-16\right)=2\)
\(\Rightarrow3x=16+2\)
\(\Rightarrow3x=18\)
\(\Rightarrow x=18:3\)
\(\Rightarrow x=6\)
Hc tốt
\(\left(3x-2^4\right)\times7^{10}=2\times7^{10}\)
\(3x-2^4=2\times7^{10}:7^{10}\)
\(3x-2^4=2\times1\)
\(3x-16=2\)
\(3x=18\)
\(x=6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2x+10⋮x+1\)
\(\Rightarrow2x+2+8⋮x+1\)
\(\Rightarrow2\left(x+1\right)+8⋮x+1\)
\(\Rightarrow x+1\inƯ\left(8\right)=\left\{\pm1;\pm2;\pm4;\pm8\right\}\)
\(x\in\left\{0;1;-2;\pm3;-5;7;-9\right\}\)
\(2x+10⋮x-1\)
\(\Rightarrow2x-2+12⋮x-1\)
\(\Rightarrow2\left(x-1\right)+12⋮x-1\)
\(\Rightarrow x-1\inƯ\left(12\right)=\left\{\pm1;\pm2;\pm3;\pm4;\pm6;\pm12\right\}\)
x - 1 = 1 => x = 2
x -1 = -1 => x = 0
... tg tự
( 3x - 10 ) : 10 = 20
3x - 10 = 20 : 10
3x - 10 = 2
3x = 2 + 10
3x = 12
x = 12 : 3
x = 4
3x-10=200
3x=210
x=70