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\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
<=> \(\frac{10}{3}x+\frac{67}{4}=-\frac{53}{4}\)\(\frac{10}{3}x=-\frac{53}{4}-\frac{67}{4}\)=> \(\frac{10}{3}x=-\frac{120}{4}=-30\)
<=> X=(-3)*3 => X=-9
Đáp số: x=-9
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3\frac{1}{3}.x+16\frac{3}{4}=-13,25\)
\(\frac{10}{3}x+16,75=-13,25\)
\(\frac{10}{3}x=-13,25-16,75\)
\(\frac{10}{3}x=-30\)
\(x=-9\)
Vậy \(x=-9\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
\(\Leftrightarrow\frac{3\times3+1}{3}x+\frac{16\times4+3}{4}=-13,25\)
\(\Leftrightarrow\frac{9+1}{3}x+\frac{64+3}{4}=-13,25\)
\(\Leftrightarrow\frac{10}{3}x+\frac{67}{4}=-13,25\)
\(\Leftrightarrow\frac{10}{3}x+16,75=-13,25\)
\(\Leftrightarrow\frac{10}{3}x=-13,25-16,75\)
\(\Leftrightarrow\frac{10}{3}x=-30\)
\(\Leftrightarrow x=-30\div\frac{10}{3}\)
\(\Leftrightarrow x=\frac{-30}{1}\times\frac{3}{10}\)
\(\Leftrightarrow x=\frac{-90}{10}\)
\(\Leftrightarrow x=-9\)
![](https://rs.olm.vn/images/avt/0.png?1311)
= 10/3.x+ 67/4=-53/4
10/3.x=-53/4-67/4
10/3.x=-30
x=-30:10/3
x=-9
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3\frac{1}{3}y+16\frac{3}{4}=13,25\)
\(\Rightarrow\frac{10}{3}y+\frac{67}{4}=13\frac{1}{4}\)
\(\Rightarrow\frac{10}{3}y+\frac{67}{4}=\frac{53}{4}\)
\(\Rightarrow\frac{10}{3}y=\frac{53}{4}-\frac{67}{4}\)
\(\Rightarrow\frac{10}{3}y=\frac{-14}{4}\)
\(\Rightarrow y=-\frac{14}{4}:\frac{10}{3}\)
\(\Rightarrow y=-\frac{14}{4}.\frac{3}{10}\)
\(\Rightarrow y=\frac{-21}{20}\)
Chúc bạn học tốt !!!
![](https://rs.olm.vn/images/avt/0.png?1311)
\((2,7.x-1\frac{1}{2})\div\frac{2}{7}=\frac{-21}{4}\) \(3\frac{1}{3}.x+16\frac{3}{4}=-13.25\)
\(2,7.x-1\frac{1}{2}=-\frac{21}{4}\cdot\frac{2}{7}\) \(\frac{10}{3}.x+\frac{67}{4}=-13.25\)
\(2,7.x-\frac{3}{2}=-\frac{3}{2}\) \(\frac{10}{3}.x+\frac{67}{4}=-\frac{53}{4}\)
\(2,7.x=-\frac{3}{2}+\frac{3}{2}\) \(\frac{10}{3}.x=-\frac{53}{4}-\frac{67}{4}\)
\(2,7.x=0\) \(\frac{10}{3}.x=-30\)
\(x=0:2,7\) \(x=-30:\frac{10}{3}\)
\(x=0\) \(x=-9\)
Vậy x=0 Vậy x= -9
\(\left(4.5-2.x\right):\frac{3}{4}=1\frac{1}{3}\) \(1.5+1\frac{1}{4}.x=\frac{2}{3}\)
\(\left(4.5-2.x\right)=1\frac{1}{3}\cdot\frac{3}{4}\) \(1\frac{1}{4}.x=\frac{2}{3}-1.5\)
\(4.5-2.x=\frac{4}{3}\cdot\frac{3}{4}\) \(\frac{5}{4}.x=\frac{2}{3}-\frac{3}{2}\)
\(4.5-2.x=1\) \(\frac{5}{4}.x=-\frac{5}{6}\)
\(2.x=4.5-1\) \(x=-\frac{5}{6}:\frac{5}{4}\)
\(2.x=3.5\) \(x=-\frac{2}{3}\)
\(x=3.5:2\)
\(x=1.75\) Vậy \(x=-\frac{2}{3}\)
Vậy x=1.75
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{10}{3}x+\frac{67}{4}=-\frac{53}{4}\)
<=> \(\frac{10}{3}x=-30\)
=> x = -9
\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
\(\frac{10}{3}x+\frac{67}{4}=\frac{-53}{4}\)
\(\frac{10}{3}x\) =\(\frac{-53}{4}-\frac{67}{4}\)
\(\frac{10}{3}x\) =-30
\(x\) =-30:\(\frac{10}{3}\)
\(x\) =-9
\(3\frac{1}{3}x=-13,25-\frac{67}{4}\)
\(3\frac{1}{3}x=-13,25-16,75\)
\(3\frac{1}{3}x=-3,5\)
\(x=-3,5:\frac{10}{3}\)
\(x=-3,5.\frac{3}{10}\)
\(x=1,05\) hoặc \(x=\frac{105}{100}\)