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Số trung bình cộng của :
3,52; 0,71; 6,04; 5,12; 4,46 là : …………
c) \(\frac{3}{5}+\frac{3}{4}+\frac{2}{5}+\frac{5}{8}+\frac{1}{2}\)
= \(\frac{3}{5}+\frac{2}{5}+\left(\frac{6}{8}+\frac{5}{8}+\frac{4}{8}\right)\)
= 1 + \(\frac{15}{8}\)
= 2\(\frac{7}{8}\)
3/5+3/4+2/5+5/8+1/2
=(3/5+2/5)+(3/4+1/2)+5/8
=1+5/4+5/8
=1+15/8=23/8
\(1\frac{1}{3}:\left(1\frac{2}{3}-x\right)=\frac{8}{7}\)
\(\frac{4}{3}:\left(\frac{5}{3}-x\right)=\frac{8}{7}\)
\(\left(\frac{5}{3}-x\right)=\frac{4}{3}:\frac{8}{7}\)
\(\left(\frac{5}{3}-x\right)=\frac{7}{6}\)
\(x=\frac{5}{3}-\frac{7}{6}\)
\(x=\frac{1}{2}\)
Bài 2:
theo thứ tự tăng dần: \(\frac{75}{100};\)\(4\frac{1}{2};\)\(6,04;\)\(7.\)
\(1\frac{1}{3}:\left(1\frac{2}{3}-x\right)=\frac{8}{7}\Rightarrow\frac{4}{3}:\left(\frac{5}{3}-x\right)=\frac{8}{7}\)
\(\Rightarrow\frac{5}{3}-x=\frac{4}{3}:\frac{8}{7}\Rightarrow\frac{5}{3}-x=\frac{7}{6}\)
\(\Rightarrow x=\frac{5}{3}-\frac{7}{6}\Rightarrow x=\frac{1}{2}\)
\(\frac{2}{3}.\frac{4}{5}+\frac{1}{3}.\frac{4}{5}=\frac{4}{5}\left(\frac{2}{3}+\frac{1}{3}\right)=\frac{4}{5}.\frac{3}{3}=\frac{4}{5}.1=\frac{4}{5}\)
\(\frac{1}{2}:\frac{3}{4}+\frac{1}{6}:\frac{3}{4}=\frac{3}{4}:\left(\frac{1}{2}+\frac{1}{6}\right)=\frac{3}{4}:\frac{2}{3}=\frac{9}{8}\)
\(\frac{2}{3}.\frac{4}{5}-\frac{1}{3}.\frac{4}{5}=\frac{4}{5}\left(\frac{2}{3}-\frac{1}{3}\right)=\frac{4}{5}.\frac{1}{3}=\frac{4}{15}\)
\(\frac{1}{2}:\frac{3}{4}-\frac{1}{6}:\frac{3}{4}=\frac{3}{4}:\left(\frac{1}{2}-\frac{1}{6}\right)=\frac{3}{4}:\frac{1}{3}=\frac{9}{4}\)
\(\frac{2}{3}.\frac{4}{5}+\frac{1}{3}.\frac{4}{5}=\left(\frac{2}{3}+\frac{1}{3}\right).\frac{4}{5}=1.\frac{4}{5}=\frac{4}{5}\)
\(\frac{1}{2}:\frac{3}{4}+\frac{1}{6}:\frac{3}{4}=\frac{1}{2}.\frac{4}{3}+\frac{1}{6}.\frac{4}{3}=\left(\frac{1}{2}+\frac{1}{6}\right).\frac{4}{3}=\frac{2}{3}.\frac{4}{3}=\frac{8}{9}\)
c,d tương tự
