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\(2\times30-x-x=52\)
\(60-2x=52\)
\(-2x=52-60\)
\(-2x=-8\)
\(x=\left(-8\right):\left(-2\right)\)
\(x=4\)
Vậy \(x=4\)
2 x 30 - X - X = 52
60 = 52 + X x 2
60 - 52 = X x 2
8 = X x 2
8 : 2 = X
4 = X
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a) \(30\left(x+2\right)-6\left(x-5\right)-24x=100\)
\(\Leftrightarrow30x+60-6x+30-24x=100\)
\(\Leftrightarrow\left(30x-6x-24x\right)+\left(60+30\right)\)
\(\Leftrightarrow x\left(30-6-24\right)+90=100\)
\(\Leftrightarrow0x+90=100\)
\(\Leftrightarrow0x=100-90\)
\(\Leftrightarrow0x=10\)
\(\Rightarrow\)Không có x thoả mãn.
b) \(|2x-5|=13\)
\(\Rightarrow\orbr{\begin{cases}2x-5=13\\2x-5=-13\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x=18\\2x=-8\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=9\\x=-4\end{cases}}\)
Vậy \(x\in\left\{-4;9\right\}\)
c) \(52-|x|=80\)
\(\Leftrightarrow|x|=52-80\)
\(\Leftrightarrow|x|=-28\)
Vì \(|x|\ge0\)
\(\Rightarrow\)Không có x thoả mãn.
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52 x 44 + 84 x 52 + 52 - 52 x 29
= 52 x ( 44 + 84 + 1 - 29 )
= 52 x 100
= 5200
nkớ k nhoa =33
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a) \(19\times\left(52+38\right)-9\times\left(52+38\right)=\)
\(=\) \(19\times90-9\times90\)
\(=90\times\left(19-9\right)\)
\(=90\times10\)
\(=900\)
b) \(\dfrac{2}{5}\div\dfrac{3}{7}\times\dfrac{3}{7}\div\dfrac{2}{5}+2019=\)
\(=\left(\dfrac{2}{5}\div\dfrac{2}{5}\right)\times\left(\dfrac{3}{7}\div\dfrac{3}{7}\right)+2019\)
\(=1\times1+2019\)
\(=2019\)
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X x 52 + X x 48 = 4200
=>Xx(52+48)=4200
Xx100=4200
X=4200:100
X=42
Vậy X=42
X x 52 + X x 48 = 4200
X x ( 52 + 48 ) = 4200
X x 100 = 4200
X = 4200 : 100
X = 42
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786 x ( 52 + 18 ) + 232 x ( 18 + 52 )
= 786 x 70 + 232 x 70
= 70 x ( 786 + 232 )
= 70 x 1018
= 71260
786 x ( 52 + 18 ) + 232 x ( 18 + 52 )
= 786 x 70 + 232 x 70
= 70 x ( 786 + 232 )
= 70 x 1018
= 71260