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\(||2x|+1|.3^{2015}+3^0=3^{2016}+1\)
\(\Leftrightarrow||2x|+1|.3^{2015}+1=3^{2016}+1\)
\(\Leftrightarrow||2x|+1|.3^{2015}=3^{2016}\)
\(\Leftrightarrow||2x|+1|=3\)
\(\Leftrightarrow\orbr{\begin{cases}|2x|+1=3\\|2x|+1=-3\end{cases}\Leftrightarrow\orbr{\begin{cases}|2x|=2\left(\text{chọn}\right)\\|2x|=-4\left(\text{loại}\right)\end{cases}}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=2\\2x=-2\end{cases}\Leftrightarrow\orbr{\begin{cases}x=1\\x=-1\end{cases}}}\)
\(\text{Vậy}:S=\left\{-1;1\right\}\)
\(||2x|+1|3^{2015}+3^0=3^{2016}+1\)
\(\Rightarrow||2x|+1|3^{2015}+1=3^{2016}+1\)
\(\Rightarrow||2x|+1|3^{2015}=3^{2016}+1-1\)
\(\Rightarrow||2x|+1|3^{2015}=3^{2016}\)
\(\Rightarrow||2x|+1|=3^{2016}\div3^{2015}\)
\(\Rightarrow||2x|+1|=3\)
\(\Rightarrow\orbr{\begin{cases}|2x|+1=3\\|2x|+1=-3\end{cases}\Rightarrow\orbr{\begin{cases}|2x|=3-1\\|2x|=-3-1\end{cases}\Rightarrow}\orbr{\begin{cases}|2x|=2\\|2x|=-4\end{cases}}}\)
\(\Rightarrow|2x|=2\)
\(\Rightarrow\orbr{\begin{cases}2x=2\\2x=-2\end{cases}\Rightarrow\orbr{\begin{cases}x=2\div2\\x=-2\div2\end{cases}\Rightarrow}\orbr{\begin{cases}x=1\\x=-1\end{cases}}}\)
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Hello bạn, mk cx tên Mai nek.
\(\frac{2}{5}.\left(x-1\right)+1=\frac{3}{5}\)
\(\Rightarrow\frac{2}{5}\left(x+1\right)=\frac{3}{5}-1\)
\(\Rightarrow\frac{2}{5}\left(x+1\right)=-\frac{2}{5}\)
\(\Rightarrow x+1=-\frac{2}{5}:\frac{2}{5}\)
\(\Rightarrow x+1=-1\)
\(\Rightarrow x=-1-1\)
\(\Rightarrow x=-2\)
\(\left(\frac{2}{7}\times x+1\right)\times\left(3-\frac{1}{2}\times x\right)=0\)
\(TH1:\frac{2}{7}\times x+1=0\)
\(\frac{2}{7}\times x=-1\)
\(x=-\frac{2}{7}\)
\(TH2:3-\frac{1}{2}\times x=0\)
\(\frac{1}{2}\times x=3\)
\(x=\frac{3}{2}\)
Vậy \(x\in\left\{\frac{3}{2};-\frac{2}{7}\right\}\)
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a, - { -(2016 +2015) - [ - (2016 - 2015) - (2016+2015) ] }
= -{-(2016+2015)-[-0-0]}
= -{-4031-0-0}
=-4031
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![](https://rs.olm.vn/images/avt/0.png?1311)
B2:
a)3x+2=4
3x=4-2
3x=2
x=2/3
b)3(x-1)-5=-20
3(x-1)=-20+5
x-1=-15/3
x-1=-5
x=-5+1
x=-4
c)(x-1)(x+2)=0
nên x-1=0 hoặc x+2=0
x=0+1 x=0-2
x=1 x=-2
d)(x+1)(2x-5)=0
nên x+1=0 hoặc 2x-5=0
x=0-1 2x=0+5
x=1 x=5/2
còn b1 thì cậu đăng câu khác đi, t lười làm
bài 1: a) 1+(-2)+3+(-4)+5+(-6)+....+2015+(-2016)
=[1+(-2)]+[3+(-4)]+[5+(-6)]+....+[2015+(-2016)]
=(-1)+(-1)+(-1)+...+(-1) (có 1008 số -1)
=(-1).1008
=-1008