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a: \(7\cdot\left(-2\right)^3-12\cdot\left(-5\right)+\left(-17\right)\)
\(=7\cdot\left(-8\right)+60-17\)
=-56+43
=-13
b: \(1632-37-\left(-157\right)-163-1532\)
\(=\left(1632-1532\right)-37-163+157\)
=100-200+157
=57
c: \(47\cdot\left(-918\right)+\left(-53\right)\cdot918\)
\(=918\left(-47\right)+\left(-53\right)\cdot918\)
\(=918\cdot\left(-47-53\right)\)
\(=918\left(-100\right)=-91800\)
d: \(\left(-52\right)\cdot\left(-281\right)+\left(-52\right)\cdot181\)
\(=\left(-52\right)\left(-281+181\right)\)
\(=\left(-52\right)\cdot\left(-100\right)=5200\)
a: 7⋅(−2)3−12⋅(−5)+(−17)7⋅(−2)3−12⋅(−5)+(−17)
=7⋅(−8)+60−17=7⋅(−8)+60−17
=-56+43
=-13
b: 1632−37−(−157)−163−15321632−37−(−157)−163−1532
=(1632−1532)−37−163+157=(1632−1532)−37−163+157
=100-200+157
=57
c: 47⋅(−918)+(−53)⋅91847⋅(−918)+(−53)⋅918
=918(−47)+(−53)⋅918=918(−47)+(−53)⋅918
=918⋅(−47−53)=918⋅(−47−53)
=918(−100)=−91800=918(−100)=−91800
d: (−52)⋅(−281)+(−52)⋅181(−52)⋅(−281)+(−52)⋅181
=(−52)(−281+181)=(−52)(−281+181)
=(−52)⋅(−100)=5200=(−52)⋅(−100)=5200
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a)29 . (19 – 13) – 19 . (29 – 13)
= 29 . 6 – 19 . 16
= 174 – 304
= –130.
b)31.(-18)+31.(-81)-31
= 31. [-18 + (-81) - 1 ]
= 31. (-100)
= -3100
c)(7.3-3):(-6)
(7.3-3):(-6)
= (21-3):(-6)
= 18 : (-6)
= 3
d)72:[(-6).2+4)]
= 72 : ( -12 + 4 )
= 72 : -8
= -9
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Đặt
\(A=\left(-2\right)+7+\left(-12\right)+17+.....+\left(-52\right)+57\)
\(A=\left[\left(-2\right)+7\right]+\left[\left(-12\right)+17\right]+.....+\left[\left(-52\right)+57\right]\)
\(A=5+5+5+.....+5\)(11 cặp)
\(A=5.11=55\)
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a: =25x100-150=2500-150=2350
c: \(=520:\left\{515\cdot25\right\}\)
=104/2575
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(-2)+7+(-12)+17+.......+(-52)+57
= [(-2)+7]+[(-12)+17]+...+[(-52)+57]
= 5+5+...+5 có 6 số 5
= 5.6
= 30
\(\frac{2}{2\times7}+\frac{2}{7\times12}+..+\frac{2}{47\times52}=\frac{2}{5}\left(\frac{1}{2}-\frac{1}{7}\right)+\frac{2}{5}\left(\frac{1}{7}-\frac{1}{12}\right)+..+\frac{2}{5}\left(\frac{1}{47}-\frac{1}{52}\right)\)
\(=\frac{2}{5}\left(\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{12}+..+\frac{1}{47}-\frac{1}{52}\right)=\frac{2}{5}\times\left(\frac{1}{2}-\frac{1}{52}\right)=\frac{5}{26}\)