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\(\frac{22}{25}.\left(\frac{5}{11}-\frac{8}{9}\right)-\frac{8}{9}\left(\frac{27}{4}-\frac{22}{25}\right)\)
\(\frac{22}{25}.\left(\frac{5}{11}-\frac{8}{9}\right)-\frac{8}{9}.\left(\frac{27}{4}-\frac{22}{25}\right)=\frac{22}{25}.\frac{5}{11}-\frac{22}{25}.\frac{8}{9}-\frac{8}{9}.\frac{27}{4}+\frac{8}{9}.\frac{22}{25}=\frac{2}{5}-\frac{6}{1}=\frac{-28}{5}\)
a: \(=\dfrac{3}{5}:\dfrac{7}{5}=\dfrac{3}{5}\cdot\dfrac{5}{7}=\dfrac{3}{7}\)
b: \(=\dfrac{9}{17}\left(\dfrac{8}{5}-\dfrac{3}{5}\right)+\dfrac{8}{17}\)
=9/17+8/17=1
c: =>x-3/10=7/15*1/5=7/75
=>x=7/75+3/10=59/150
Answer:
\(\left(1+\frac{8}{10}\right).\left(1+\frac{8}{22}\right).\left(1+\frac{8}{36}\right)...\left(1+\frac{8}{8352}\right)\)
\(=\frac{18}{10}.\frac{30}{22}.\frac{44}{36}...\frac{8360}{8352}\)
\(=\frac{2.9.3.10.4.11....88.95}{1.10.2.11.3.12...87.96}\)
\(=\frac{\left(2.3.4...8\right).\left(9.10.11...95\right)}{\left(1.2.3...87\right).\left(10.11...96\right)}\)
\(=\frac{9.88}{96}\)
\(=\frac{3}{4}\)
1:
a: \(35\cdot16+35\cdot28-44\cdot15\)
\(=35\left(16+28\right)-44\cdot15\)
\(=44\left(35-15\right)\)
\(=44\cdot20=880\)
b: \(240-2\left(3\cdot5^2-20:2^2\right)\)
\(=240-2\left(3\cdot25-20:4\right)\)
\(=240-150+10=10+90=100\)
2:
b: \(\left(8-3x\right)^4-1=15\)
=>\(\left(3x-8\right)^4=16\)
=>\(\left[{}\begin{matrix}3x-8=2\\3x-8=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=10\\3x=6\end{matrix}\right.\)
=>x=10/3 hoặc x=2
c: \(218-5\left(x-8\right)=2^5:2^2\)
=>\(218-5\left(x-8\right)=2^3=8\)
=>5(x-8)=210
=>x-8=42
=>x=50
d: \(\left(5-3x\right)^4-1=15\)
=>\(\left(3x-5\right)^4-1=15\)
=>\(\left(3x-5\right)^4=16\)
=>\(\left[{}\begin{matrix}3x-5=-4\\3x-5=4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=1\\3x=9\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=3\end{matrix}\right.\)
\(\dfrac{3}{8}+\dfrac{-11}{8}=1\)
\(\dfrac{22}{9}+\dfrac{10}{18}=3\)
1<x<3
=>x=2
\(\left(\frac{15}{8}-\frac{9}{13}\right)+\left(\frac{22}{13}-\frac{5}{8}\right)\)
\(=\left(\frac{15}{8}-\frac{5}{8}\right)+\left(\frac{22}{13}-\frac{9}{13}\right)\)
\(=\frac{10}{8}+\frac{13}{8}\)
\(=\frac{23}{8}\)
(15/8-9/13)+(22/13-5/8)= (15/8-5/8)-(9/13-22/13)=10/8-(-1)=9/4)
=14
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