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6)
(19-x)-46=-12
19-x=-12+46
19-x=34
x=19-34
x=-15
7)=>x-2=0
x=0+2
x=2
8)=>5-x=2
x=5-2
x=3
9) đề thiếu
10)=>x+1=9
x=9-4
x=8
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =25(15+45*3)
=25*150
=3750
b: \(=-10\left(25+75-50\right)=-10\cdot50=-500\)
c: =>3^x-2=27
=>x-2=3
=>x=5
d: =>2x-5=-4
=>2x=1
=>x=1/2
e: =>2(x-1)^2=32
=>(x-1)^2=16
=>x-1=4 hoặc x-1=-4
=>x=-3 hoặc x=5
f: =>25(x+3)=75
=>x+3=3
=>x=0
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x\left(x-2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x-2=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=2\end{cases}}\)
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a) => (35:x+3)*15 = 165-15=150
=> 35:x+3 = 150:15=10
=> 35:x = 10-3 = 7
=> x = 35:7 = 5
b) => 1*3/10x :1/2 +4/5 =1
=> 1*3/10x:1/2 =1-4/5=1/5
=> 1*3/10x = 1/5 *1/2 =1/10
=> 3/10-x = 1/10
=> x = 3/10 - 1/10 = 2/10 = 1/5
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{7}{-25}+\dfrac{18}{25}+\dfrac{4}{23}+\dfrac{5}{7}+\dfrac{19}{23}\)
=\(\left(\dfrac{-7}{25}+\dfrac{18}{25}\right)+\left(\dfrac{4}{23}+\dfrac{19}{23}\right)+\dfrac{5}{7}\)
= \(\dfrac{11}{25} +1+\dfrac{5}{7}\)
= \(1\dfrac{11}{25}+\dfrac{5}{7}\)
= \(2\dfrac{27}{175}\)
b) \(-2+\dfrac{15}{19}+\dfrac{-15}{17}+\dfrac{15}{23}+\dfrac{4}{19}\)
=\(-2+\left(\dfrac{ }{ }\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\frac{-19}{6}+\frac{-15}{2}+\frac{11}{3}\)
\(=\frac{-19}{6}+\frac{-45}{6}+\frac{22}{6}\)
\(=\frac{-19-45+22}{6}\)
\(=\frac{-42}{6}=-7\);
\(\frac{-5}{4}+\frac{19}{12}+\frac{-10}{3}\)
\(=\frac{-15}{12}+\frac{19}{12}+\frac{-40}{12}\)
\(=\frac{-15-40+19}{12}\)
\(=\frac{-36}{12}=-3\)
\(\Rightarrow-7< x\le-3\)
\(\Rightarrow x=-6;-5;-4;-3\)
Nhớ k
thêm dấu ngoặc ở 1x=15/25+-19/25
chỗ -19/25 ấy :vv