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Bài 2: Tính nhanh
a) 29 + 132 + 237 + 868 + 3
= 29+(132+858)+(237+3)
=29+990+240
=1259
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\(491.\left(267+53\right)-491.\left(153+67\right)\)
\(=491.\left[267+53-125-67\right]\)
\(=491.100=49100\)
491.(267+53)-491.(153+67)=491.(267+53-153-67)=491.100=49100
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135*57+135*86-35*143= 135 (57+86)-35*143=135*143-35*143=143 (135-35)=143*100=14300
91*47+49*53-18*47+24*53=(91*47-18*47)+(49*53+24*53)=47*(91-18)+53*(49+24)=47*73+53*73=73*(47+53)=73*100=7300
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a) Ta có |–8| = 8; |–4| = 4.
Do đó: |–8| – |–4| = 8 – 4 = 4.
b) Ta có: |–7| = 7; |–3| = 3.
Do đó : |–7| . |–3| = 7 . 3 = 21.
c) Ta có: |18| = 18; |–6| = 6.
Do đó: |18| : |–6| = 18 : 6 = 3.
d) Ta có: |153| = 153; |–53| = 53.
Do đó : |153| + |–53| = 153 + 53 = 206.
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a: =(1-2-3+4)+(5-6-7+8)+...+(21-22-23+24)
=0+0+...+0
=0
b: =-7111+53+711-153=-6400-100=-6500
c: =-43(-1-296+296)=-43*(-1)=43
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a) 491 x (267+53) - 491 x ( 153 + 67 )
=491x<(267+53) - (153+67)>
=491x<300-200>
=491x100
=49100
b) 53 x 39 + 47 x 39 - 53 x 21 - 47 x 21
=53x(39-21) - 47x(39-21)
=53x18-47x18
=18x(53-47)
=18x6
=108
bạn ơi cho mình sửa phần b) nha
b) 53 x 39 + 47 x 39 - 53 x 21 - 47 x 21
=53x(39-21) + 47x(39-21)
=53x18+47x18
=18x(53+47)
=18x100
=1800
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46 + 29 = ( 46 – 1 ) + (29 + 1) (thêm bớt 1 đơn vị)
= 45 + 30 = 75.
hoặc 46 + 29 = (46 + 4) + (29 – 4) (thêm bớt 4 đơn vị)
= 50 + 25 = 75.
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35 + 98 = (35 – 2 ) + (98 + 2 ) (thêm bớt 2 đơn vị)
= 33 + 100 = 133
1.
2^3 . 4^4 . 16^2
= 2^3 . 2^8 . 2^8
= 2^19
2.
8^6 : 2^3
= 2^18 : 2^3
= 2^15
Mấy câu kia tương tự thôi :D
1) 23.46.162=23.(22)6.(24)2=23.212.28= 223
2) 86 : 23 = (23)6 : 23 = 218 : 23 = 215
3) 273:33 =(33)3 : 33 = 39 : 33 = 36
4) 153 : 53 = (3.5)3 : 53 = 33