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\(a,=8\left(x^3-125\right)=8\left(x-5\right)\left(x^2+10x+25\right)\\ b,=\left(0,1+4x\right)\left(0,01-0,4x+16x^2\right)\\ d,=\left(3x-\dfrac{1}{2}y\right)\left(9x^2+\dfrac{3}{2}xy+\dfrac{1}{4}y^2\right)\\ c,=\left(\dfrac{1}{5}y+x\right)\left(\dfrac{1}{25}y^2-\dfrac{1}{5}xy+x^2\right)\)
a, 8x3- 1000 = (2x)3 - 103 = (2x -10). (4x2 + 20x +100)
b,\(0,001+64x^3=\left(\dfrac{1}{10}\right)^3+\left(4x\right)^3=\left(\dfrac{1}{10}+4x\right).\left(\dfrac{1}{100}-\dfrac{2}{5}x+16x^2\right)\)
c, \(\dfrac{1}{125}y^3+x^3=\left(\dfrac{1}{5}y\right)^3+x^3=\left(\dfrac{1}{5}y+x\right).\left(\dfrac{1}{25}y^2-\dfrac{1}{5}yx+x^2\right)\)
\(d,27x^3-\dfrac{1}{8}y^3=\left(3x\right)^3-\left(\dfrac{1}{2}y\right)^3=\left(3x-\dfrac{1}{2}y\right).\left(9x^2+\dfrac{3}{2}xy+\dfrac{1}{4}y^2\right)\)
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a)
\(=\left(x+2y\right)\left(x^2-xy+y^2\right)-3xy\left(x+2y\right)\)
\(=\left(x+2y\right)\left(x^2-xy+y^2-3xy\right)\)
\(=\left(x+2y\right)\left(x^2-2xy+y^2\right)\)
\(=\left(x+2\right)\left(x-2\right)^2\)
b)
\(3x\left(2x-1\right)\left(2x+1\right)=0\)
3x=0 =>x=0
hoặc 2x-1=0 => 2x=1=>x=1/2
hoặc 2x+1=0=>2x=-1=>x=-1/2
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