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a) Ta có: \(19\cdot64+36\cdot19\)
\(=19\cdot\left(64+36\right)\)
\(=19\cdot100=1900\)
b) Ta có: \(150-\left[10^2-\left(14-11\right)^2\cdot2700^0\right]\)
\(=150-\left[100-3^2\cdot1\right]\)
\(=150-91\)
\(=69\)
c) Ta có: \(22^3-\left(1^{10}+8\right):3^2\)
\(=22^3-\left(1+8\right):3^2\)
\(=22^3-9:9\)
\(=22^3-1\)
\(=10647\)
d) Ta có: \(59-\left[90-\left(17-8\right)^2\right]\cdot1^{4514}\)
\(=59-\left[90-9^2\right]\cdot1\)
\(=59-\left(90-81\right)\)
\(=59-9=50\)
e) Ta có: \(7^2-36:3^2\)
\(=7^2-36:9\)
\(=49-4=45\)
![](https://rs.olm.vn/images/avt/0.png?1311)
C = (12 x 14) + 23 / 1423 < (13 x 14) + 12
Ta thấy: (12 x 14) + 23 < (13 x 14) + 12
D = 12 + (23 x 14) / 1423
Do:12 + (23 x 14) > (13 x 14) + 12
Nên: D > C
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài làm
a) 11 - 12 + 13 - 14 + 15 - 16 + 17 - 18 + 19 - 20
= ( 11 - 12 ) + ( 13 - 14 ) + ( 15 - 16 ) + ( 17 - 18 ) + ( 19 - 20 )
= ( -1 ) + ( -1 ) + ( -1 ) + ( -1 ) + ( -1 )
= -5
b) 101 - 102 - ( - 103 ) - 104 - ( - 105 ) - 106 - ( - 107 ) - 108 - ( - 109 ) - 110
= 101 - 102 + 103 - 104 + 105 - 106 + 107 - 108 + 109 - 110
= ( 101 - 102 ) + ( 103 - 104 ) + ( 105 - 106 ) + ( 107 - 108 ) + ( 109 - 110 )
= ( -1 ) + ( -1 ) + ( -1 ) + ( -1 ) + ( -1 )
= -5
# Học tốt #
a)11 - 12 + 13 - 14 + 15 - 16 + 17 - 18 + 19 - 20
= (11 - 12) + (13 - 14) + (15 - 16) + (17 - 18) + ( 19 - 20)
= (-1) + (-1) + (-1) + (-1) + (-1) = (-1) . 5 = - 5
b)101-102-(-103)-104-(-105)-106-(-107)-108-(-109)-110
= 101-102+103-104+105-106+107-108+109-110
= (101-102)+(103-104)+(105-106)+(107-108)+(109-110)
= (-1) + (-1) + (-1) + (-1) + (-1)
= (-1) . 5
= -5
![](https://rs.olm.vn/images/avt/0.png?1311)
a)Tu so:
15.8+15.4
=5.3.2.4+5.3.4
=12.10+12.5
=12.15
=>\(\frac{12.15}{12.3}=\frac{12}{12}.\frac{15}{3}=\frac{15}{3}=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a,11-12+13-14+15-16+17-18+19-20
=(11-12)+(13-14)+(15-16)+(17-18)+(19-20)
=(-1)+(-1)+(-1)+(-1)+(-1)
=-5
b,101-102-(-103)-104-(-105)-106-(-107)-108-(-109)-110
=101-102+103-104+105-106+107-108+109-110
=(101-102)+(103-104)+(105-106)+(107-108)+(109-110)
=(-1)+(-1)+(-1)+(-1)+(-1)
=-5
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
\(\frac{102}{97}>1;\frac{99}{101}< 1\) nên \(\frac{102}{97}>\frac{99}{101}\)
Hok tốt
ta có: 102/97 > 99/97> 99/101
suy ra: 102/97> 99/101
ta có : -5.11 = -55 > 14. -4 = -56
suy ra -5/14 > -4/11
150-{102-(14-11)2.20070}
=150-(102-32.20070)
=150-(100-9-1)
=150-90
=60
150− [102 − (14 − 11)2.20070]
= 150 − [100 − 32.1]
= 150 − 91
= 69