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Lời giải:
$128-[68+8(37-35)^2]:4=128-(68+8.2^2):4$
$=128-100:4=128-25=103$
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128 - [68 + 8(37 - 35)2 ] : 4
= 128 - [68 + 8.22 ] : 4
= 128 - [68 + 32] : 4
= 128 - 100 : 4
= 128 - 25
= 103
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\(128.\left[68+8\left(37-35\right)^2\right]\)
\(=128\left[68+8.2^2\right]\)
\(=128\left[68+32\right]\)
\(=128.100\)
\(=12800\)
128[68+8(37-35)^2]
=128[68+8.2^2]
=128[68+8.4]
=128[68+32]
=128.100
=12800
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a , 2014+(-1999)+1986+175+(-2001) = (2014+1986)+(-1999+-2001)+175
= 4000 + -4000 +175
= 175
roi tu lam nhe minh ban roi phai day
nice to meet you
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a: \(=47-\left[\left(45\cdot16-25\cdot12\right):14\right]\)
\(=47-30=17\)
b: \(=50-\left[6+34\right]\)
=50-40
=10
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(-12).32+240:(-2)2=(-12).9+240:4=(-108)+60= -48
128-[68+8(37-35mũ 2 ]:4
=128-[68+8(37-1225]:4
=128-[68+8.(-1188)]:4
=128-[68+(-9504)]:4
=128-(-9436):4
=128-(-2359)
=2487
128-[68+8(37-35mũ 2 ]:4
=128-[68+8(37-1225]:4
=128-[68+8.(-1188)]:4
=128-[68+(-9504)]:4
=128-(-9436):4
=128-(-2359)
=2487