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a)6x=10y=>x/10=y/6=>x/50=y/30
10y=15z=>y/15=z/10=>y/30=z/20
x+y+z/50+30+10=90/90=1
x=50;y=30;z=10
b)đề 2 có sai ko z pn
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\(a,\Rightarrow\left[{}\begin{matrix}x-\dfrac{2}{3}=\dfrac{5}{4}\\\dfrac{2}{3}-x=\dfrac{5}{4}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{23}{12}\\x=-\dfrac{7}{12}\end{matrix}\right.\\ b,\Rightarrow0,1x\cdot1,35=0,2\cdot1,25=0,25\\ \Rightarrow0,135x=0,25\Rightarrow x=\dfrac{50}{27}\\ c,ĐK:x\ge0\\ PT\Leftrightarrow-2\sqrt{x}=-6\Leftrightarrow x=9\left(tm\right)\\ d,\Leftrightarrow3^{x+2}\cdot2^{x-1}=\left(3^2\cdot2^2\right)^3=3^6\cdot2^6\\ \Leftrightarrow\left\{{}\begin{matrix}x+2=6\\x-1=6\end{matrix}\right.\Leftrightarrow x\in\varnothing\)
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\(2^x+2^{x-1}+2^{x+2}=28\)
=>\(2^x+\dfrac{1}{2}\cdot2^x+2^x\cdot4=28\)
=>\(2^x\cdot5.5=28\)
=>\(2^x=\dfrac{56}{11}\)
=>\(x=log_2\left(\dfrac{56}{11}\right)\)
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a) 4/7.|x| + 1/28 = 12/28
4/7.|x| = 11/28
|x| = 11/16
=> x = 11/16
b) (2)2x-1 = 8 = 23
=> 2x + 1 = 3
2x = 2
x = 1
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\(\frac{1}{2}.2^x+2^{x+2}=2^8+2^5\)
\(2^x\left(\frac{1}{2}+4\right)=288\)
\(2^x=64\)
\(2^x=2^6\Leftrightarrow x=6\)
Vậy x=6