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=\(-2017+1 . ( -2018 +1 ) \)
\(= -2017+1 . -2017\)
= -2017+ -2017
= -4034
![](https://rs.olm.vn/images/avt/0.png?1311)
a, Vì -2018 khác 0
=> x-11=0
=> x=11
b, Vì -2018 < 0
=> x+13 > 0
=> x > -13
c, Vì 2018 > 0 => 2x-10 > 0
=> 2x > 10
=> x > 5
d, => x-3=0 hoặc 3x-9=0
=> x=3
e, Vì x-1 < x+5
=> x-1 < 0 và x+5 > 0
=> x < 1 và x > -5
=> -5 < x < 1
Tk mk nha
![](https://rs.olm.vn/images/avt/0.png?1311)
(5^2018+5^2018+5^2018+5^2018) + 5^2018 -5x=0
5^2018+5^2018+5^2018+5^2018+5^2018-5x =0
5(5^2018)-5x =0
5x =5(5^2018)-0
5x =5(5^2018)
Suy ra x= 5^2018
Vậy: x= 5^2018
![](https://rs.olm.vn/images/avt/0.png?1311)
|- 2017| + 12018(|- 2018| + 20160)
= 2017 + 1(2018 + 1)
= 2017 + 1.2019
= 2017 + 2019
= 4036
![](https://rs.olm.vn/images/avt/0.png?1311)
|-2017|+12018(|-2018|+20160)
=2017+1(2018+2016)
=2018(2018+2016)
=2018.4034
=8140612
I - 2017 I + 12018 ( I - 2018 I + 20160 )
= 2017 + 1 . ( 2018 + 1 )
= 2017 + 1 . 2019
= 2017 + 2019
= 4036
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Leftrightarrow\left(x-2018\right)^{x+1}-\left(x-2018\right)^{x+1}.\left(x-2018\right)^{10}=0\)
\(\Leftrightarrow\left(x-2018\right)^{x+1}\left(1-\left(x-2018\right)^{10}\right)=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(x-2018\right)^{x+1}=0\\1-\left(x-2018\right)^{10}=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x-2018=0\\\left(x-2018\right)^{10}=1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=2018\\x=2019\end{matrix}\right.\)
12018=1
20180=1
hok tốt
\(1^{^{ }2018}=1\)
\(2018^0=1\)