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2 tháng 8 2015

\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)

\(=\frac{28}{15}.\frac{3}{4}-\left(\frac{8}{15}+\frac{1}{4}\right).\frac{8}{9}-\frac{51}{13}.\frac{1}{3}\)

\(=\frac{7}{5}-\left(\frac{32}{60}+\frac{15}{60}\right).\frac{8}{9}-\frac{17}{13}\)

\(=\frac{7}{5}-\frac{47}{60}.\frac{8}{9}-\frac{17}{13}\)

\(=\frac{7}{5}-\frac{94}{135}-\frac{17}{13}\)

\(=\frac{-212}{351}\)

Tự quy đồng

 

\(2\frac{3}{4}.\left(-0,4\right)-1\frac{3}{5}.2,75+\left(-1,2\right):\frac{4}{11}\)

\(=\frac{11}{4}.\frac{-2}{5}-\frac{8}{5}.\frac{11}{4}-\frac{6}{5}.\frac{11}{4}\)

\(=\frac{11}{4}.\left(\frac{-2}{5}-\frac{8}{5}-\frac{6}{5}\right)\)

\(=\frac{11}{4}.\frac{-16}{5}\)

\(=\frac{-44}{5}=-8\frac{4}{5}\)

 

14 tháng 8 2020

a)2/3 + 5+3/7:2+4/49.(-7)+1/2.(-2)\(^4\)

= 2/3+5+3/14+-4/7+8

=(2/3+3/14+-4/7)+(5+8)

=13/42+13

=559/42

b)2+3/4.(-0,4)-1-3/5.2,75+(-1/2):4/11

=2+(-0,3) - 1 - 1,65 + (-11/8)

= -2,325

c)( 2 + 1/3 +3 +1/2 ) : ( -4 - 1/6 +3 +1/7 ) +7 +1/2

=35/6 : -43/42 + 7 + 1/2

= -245/43 +7 +1/2

= 155/86

d) 2/3+ -5/12

= 8/12 + -5/12

= 3/12 

e) -2/3 . -9/12 

\(\frac{-2.-9}{3.12}\)

= 18/36

=1/2

14 tháng 8 2020

f) -2/9 - 7/12

=\(\frac{-24}{108}\)-  \(\frac{14}{108}\)

\(\frac{-38}{108}\)

=\(\frac{-19}{54}\)

g) 2/3 : -4/9

\(\frac{2}{3}\)\(\frac{-9}{4}\)

= -3/2

h) 4 . ( -1/3)\(^3\)- 2 . ( -1/2)\(^2\)+3 .( 1/2 ) +1

=- 4 . 1/27 - 2 . 1/4 + 3 .1/2 +1 

= -4/27 - 1/2 + 3/2 + 1

= 50 / 27

k ) ( 4 - 5/12 ) : 2 +5/24

= 43/12 : 2 +5/24

= 43/24 + 5/24

= 48/24

= 2

a: \(\Leftrightarrow\left(\dfrac{13}{4}:x\right)\cdot\left(-\dfrac{5}{4}\right)=\dfrac{-10}{6}-\dfrac{5}{6}=\dfrac{-15}{6}=\dfrac{-5}{2}\)

\(\Leftrightarrow\dfrac{13}{4}:x=\dfrac{5}{2}\cdot\dfrac{5}{4}=\dfrac{25}{8}\)

hay \(x=\dfrac{13}{4}:\dfrac{25}{8}=\dfrac{13}{4}\cdot\dfrac{8}{25}=\dfrac{26}{25}\)

b: \(\Leftrightarrow\dfrac{3}{4}:x=\dfrac{11}{36}-\dfrac{1}{4}=\dfrac{2}{36}=\dfrac{1}{18}\)

=>\(x=\dfrac{3}{4}:\dfrac{1}{18}=\dfrac{54}{4}=\dfrac{27}{2}\)

c: \(\Leftrightarrow\left(-\dfrac{6}{5}+x\right):\left(-3.6\right)=-\dfrac{7}{4}+\dfrac{1}{4}\cdot8=\dfrac{1}{4}\)

=>x-6/5=-9/10

=>x=3/10