tìm x biết |2x-4|-|2x-10|=6
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
|2x-4|-|2x-10|=6
*2x-4\(\ge\)0\(\Leftrightarrow\)2x\(\ge4\)\(\Leftrightarrow x\ge2\):
trường hợp 1:\(2x-10\ge0\Leftrightarrow2x\ge10\Leftrightarrow x\ge5\Rightarrow x\ge5\)ta có:
2x-4-2x-10=6
2x-2x=6+4+10
0x=20(vô lý)
trường hợp 2:\(2x-10
![](https://rs.olm.vn/images/avt/0.png?1311)
(x-2)2-(x-3)(x-3)=6
x2-2.x.2+22-x2-32=6
(x2-x2)-4x+(22+32)=6
-4x+13=6
-4x=6-13=-7
x=-7:(-4)=1,75
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\frac{-x}{2}+\frac{2x}{3}+x+\frac{1}{4}+2x+\frac{1}{6}=\frac{3}{8}.\)
\(\frac{-x}{2}+\frac{2x}{3}+3x+\frac{5}{12}=\frac{3}{8}\)
\(x.\left(-\frac{1}{2}+\frac{2}{3}+3\right)+\frac{5}{12}=\frac{3}{8}\)
\(x\cdot\frac{19}{6}=-\frac{1}{24}\)
x = -1/76
b) \(\frac{3}{2x+1}+\frac{10}{4x+2}-\frac{6}{6x+3}=\frac{12}{26}\)
\(\frac{3}{2x+1}+\frac{2.5}{2.\left(2x+1\right)}-\frac{2.3}{3.\left(2x+1\right)}=\frac{6}{13}\)
\(\frac{3}{2x+1}+\frac{5}{2x+1}-\frac{2}{2x+1}=\frac{6}{13}\)
\(\frac{3+5-2}{2x+1}=\frac{6}{13}\)
\(\frac{6}{2x+1}=\frac{6}{13}\)
=> 2x + 1 = 13
2x = 12
x = 6
![](https://rs.olm.vn/images/avt/0.png?1311)
2+4+6+...+2x=210
=2(1+2+3+...+x)=210
=1+2+3+...+x=105
=x+1.x/2=105
(x+1)x=210
14.15=210
=>x=14
Vậy x=14
![](https://rs.olm.vn/images/avt/0.png?1311)
1. <=> (x-2).(2x+3) = 0
<=> x-2=0 hoặc 2x+3 = 0
<=> x=2 hoặc x=-3/2
2. <=> x^2-4x+4-x^2+9 = 0
<=> 13-4x=0
<=> 4x=13
<=> x = 13/4
3.<=>4x^2-24x+36 - 4x^2+1 = 10
<=> 37-24x = 10
<=> 24x = 37 - 10 = 27
<=> x = 27 : 24 = 9/8
k mk nha
![](https://rs.olm.vn/images/avt/0.png?1311)
2+4+6+8+10+...+2x=210
=2(1+2+3+4+5+...+x) = 210
=1+2+3+4+5+...+x=105
=x+1*x/2=105
=(x+1)x=210
=14*15=210
=> x=14
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