x-2/3:4/9= ( -0,2 ) GIUP MIK
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a 24x-15x=75+33
9x=108
x=108:9=12
b 3-2/5x=2/3
2/5x=3-2/3=1/3
x=1/3:2/5=5/6
Tk & kết bạn với mik nha
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`9/14 : 3/7 + 5/6 = 3/98 + 5/6 = 127/147`
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`4/7 xx (4 - 7/3) = 4/7 xx 5/3 = 20/21`
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a: =472x2+472x5+472x2
=472x9=4248
b: =3,6x8+7,2x4+7,2x2
=7,2(4+4+2)
=72
d: =2,4(6,2+1,9x2)=24
a: =472x2+472x5+472x2
=472x9=4248
b: =3,6x8+7,2x4+7,2x2
=7,2(4+4+2)
=72
d: =2,4(6,2+1,9x2)=24
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(\left(-2\right)^2-2x^2=-50.\)
\(\Leftrightarrow4-2x^2=-50\)
\(\Leftrightarrow2x^2-54=0\)
\(\Leftrightarrow x^2-27=0\)
\(\Leftrightarrow\left(x-3\sqrt{3}\right)\left(x+3\sqrt{3}\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=3\sqrt{3}\\x=-3\sqrt{3}\end{cases}}\)
\(\left(-2\right)^2-2x^2=-50\)
\(\Leftrightarrow x^2=\frac{-50-\left(-2\right)^2}{-2}\)
\(\Leftrightarrow x^2=27\)
\(\Leftrightarrow x=\pm\sqrt{27}\)
\(\Leftrightarrow x=\pm3\sqrt{3}\)
\(\frac{2}{x}-\frac{5}{x}=-9\)
\(\Leftrightarrow\frac{2-5}{x}=-9\)
\(\Leftrightarrow-3=-9x\)
\(\Leftrightarrow x=\frac{-3}{-9}=\frac{1}{3}\)
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a) \(-\frac{3}{4}x+\frac{1}{6}x=1-2\frac{5}{9}\)
\(\left(-\frac{3}{4}+\frac{1}{6}\right).x=1-\frac{23}{9}\)
\(-\frac{7}{12}.x=-\frac{14}{9}\)
\(x=-\frac{14}{9}:\left(-\frac{7}{12}\right)\)
\(x=\frac{8}{3}\)
Vậy x = ...
b) \(\left|2x-\frac{3}{8}\right|+2\frac{3}{4}=3\frac{1}{16}\)
\(\left|2x-\frac{3}{8}\right|+\frac{11}{4}=\frac{49}{16}\)
\(\left|2x-\frac{3}{8}\right|=\frac{49}{16}-\frac{11}{4}\)
\(\left|2x-\frac{3}{8}\right|=\frac{5}{16}\)
\(\Rightarrow\left|2x-\frac{3}{8}\right|\in\text{{}\frac{5}{16};-\frac{5}{16}\)}
Nếu, \(2x-\frac{3}{8}=\frac{5}{16}\)
\(2x=\frac{11}{16}\)
\(x=\frac{11}{32}\)
Nếu, \(2x-\frac{3}{8}=-\frac{5}{16}\)
\(2x=\frac{1}{16}\)
\(x=\frac{1}{32}\)
Vậy \(x\in\text{{}\frac{1}{32};\frac{11}{32}\)}
x - 2/3 : 4/9 = -0,2
x - 3/2 = -1/5
x = -1/5 + 3/2
x = 13/10
x= 26/45