2/3 nhân x trừ 1/2 = 3/2
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10/3 x 1/2 - ( 1/2 x X - 1/3) + 1/5 = 3/5 :1/2
5/3 - ( 1/2 x X - 1/3) + 1/5 = 6/5
5/3 - ( 1/2 x X - 1/3) = 6/5 + 1/5
5/3 - ( 1/2 x X - 1/3) = 7/5
1/2 x X - 1/3 = 5/3 - 7/5
1/2 x X - 1/3 = 4/15
1/2 x X = 4/15 + 1/3
1/2 x X = 9/15
X = 9/15 : 1/2
X = 18/15.
a) \(\frac{8}{9}\cdot x-\frac{2}{3}=\frac{1}{3}\cdot x+1\frac{1}{3}\)
=> \(\frac{8x}{9}-\frac{2}{3}=\frac{x}{3}+\frac{4}{3}\)
=> \(\frac{8x}{9}-\frac{6}{9}=\frac{x+4}{3}\)
=> \(\frac{8x-6}{9}=\frac{x+4}{3}\)
=> \(3\left(8x-6\right)=9\left(x+4\right)\)
=> \(24x-18=9x+36\)
=> \(24x-18-9x=36\)
=> \(24x-9x=54\)
=> \(15x=54\)
=> \(5x=18\)
=> \(x=\frac{18}{5}\)
Vậy x = \(\frac{18}{5}\)
b) \(\left(x-\frac{1}{2}\right)\left(\frac{3}{2}-2x\right)=0\)
=> \(\orbr{\begin{cases}x-\frac{1}{2}=0\\\frac{3}{2}-2x=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=\frac{1}{2}\\2x=\frac{3}{2}\end{cases}}\)
=> \(\orbr{\begin{cases}x=\frac{1}{2}\\x=\frac{3}{2}:2=\frac{3}{4}\end{cases}}\)
Vậy \(x\in\left\{\frac{1}{2};\frac{3}{4}\right\}\)
x * 4/3 - x *1/3 = 2/9
x * (4/3-1/3) = 2/9
x * 1 = 2/9
x = 2/9
\(x\cdot\frac{4}{3}-x\cdot\frac{1}{3}=\frac{2}{9}\)
\(x\cdot\frac{4-1}{3}=\frac{2}{9}\)
\(x\cdot1=\frac{2}{9}\)
\(x=\frac{2}{9}:1\)
\(x=\frac{2}{9}\)
\(\frac{1}{2.x}-\frac{1}{1.2}-\frac{1}{2.3}-\frac{1}{3.4}-...-\frac{1}{45.46}=-2\)
\(\frac{1}{2.x}-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{45.46}\right)=-2\)
\(\frac{1}{2.x}-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{45}-\frac{1}{46}\right)=-2\)
\(\frac{1}{2.x}-\left(1-\frac{1}{46}\right)\)
\(\frac{1}{2.x}-\frac{45}{46}=-2\)
\(\frac{1}{2.x}=-2+\frac{45}{46}\)
\(\frac{1}{2.x}=\frac{-47}{46}\)
\(2x=\frac{46}{-47}\)
\(x=\frac{46}{-47}:2=\frac{-23}{47}\)
3x(X-3)=2x(X-3)
Đề sai hả bạn làm gì có chuyện 3 và 2 nhân cùng với 1 số mà bằng nhau được
2/3 x=3/2+1/2=2
=> x=3
\(\frac{2}{3}\). x - \(\frac{1}{2}\)= \(\frac{3}{2}\)
\(\frac{2}{3}\) x = \(\frac{3}{2}\)+ \(\frac{1}{2}\)
\(\frac{2}{3}\)x = 2
x = 2 : \(\frac{2}{3}\)
x = 3/6