xong trước 5h mình vote nha, mình đg cần gấp
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
= ( - 29) . 135 + 13 . 135 +( - 2730)
= 135 . [ ( - 29) + 13] + ( - 2730) mik nghĩ là như này
= 135 . ( - 16) + ( - 2730)
= ( - 2160) + ( - 2730)
= - 4890
![](https://rs.olm.vn/images/avt/0.png?1311)
1 doesn't like
2 was reconstructed
3 have ever tried
4 will you take
5 is made
6 often rains - isn't raining
7 had
8 are standing
9 are
![](https://rs.olm.vn/images/avt/0.png?1311)
2.unless
3,unless
4,if
5.if
6.unless
7.if
8.unless
B5:
1E
2H
3A
4G
5B
6C
7F
8D
B6:
2. won't stay - find
3.hoover - will make
4.will show - wait
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Đặt A = 1 -3 + 5 - 7 + ..... + 2001 - 2003 + 2005
= (1 - 3) + (5 - 7) + ... + (2001 -2003) + 2005
= - 2 nhân 501 + 2005
= -1002 + 2005 = 1003
Đáp án là: 1003 nha!
(Nếu bạn thấy đúng thì cho một k đúng và kết bạn nha!)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)\(\left(-a+\frac{2}{3}\right)\left(a+\frac{2}{3}\right)=\left(\frac{2}{3}-a\right)\left(\frac{2}{3}+a\right)=\left(\frac{2}{3}\right)^2-a^2=\frac{4}{9}-a^2\)
b)\(\left(x+5\right)\left(x^2-5x+25\right)=x^3+5^3=x^3+125\)
c)\(\left(1-x\right)\left(x^2+x+1\right)=1-x^3\)
d)\(\left(a^2-2a+3\right)\left(a^2+2a+3\right)=\left(a^2+3\right)^2-\left(2a\right)^2=\left(a^2+3\right)^2-4a^2\)
e)\(\left(x+3y\right)\left(9y^2-3xy+x^2\right)=x^3+\left(3y\right)^3=x^3+9y^3\)
f)\(2\left(x-\frac{1}{2}\right)\left(4x^2+2x+1\right)=\left(2x-1\right)\left(4x^2+2x+1\right)=\left(2x\right)^3-1=8x^3-1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Trả lời:
Bài 1:
a, \(9x^2-4=\left(3x\right)^2-2^2=\left(3x-2\right)\left(3x+2\right)\)
b, \(x^3+27=x^3+3^3=\left(x+3\right)\left(x^2-3x+9\right)\)
c, \(8-y^3=2^3-y^3=\left(2-y\right)\left(4+2y+y^2\right)\)
d, \(x^4-81=\left(x^2\right)^2-9^2=\left(x^2-9\right)\left(x^2+9\right)\)\(=\left(x^2-3^2\right)\left(x^2+9\right)=\left(x-3\right)\left(x+3\right)\left(x^2+9\right)\)
e, \(64x^3-1=\left(4x\right)^3-1^3=\left(4x-1\right)\left(16x^2+4x+1\right)\)
f, \(x^6+8y^3=\left(x^2\right)^3+\left(2y\right)^3=\left(x^2+2y\right)\left(x^4-2x^2y+4y^2\right)\)
took => take
so => because
Doesn't => Don't
ours => our
câu này ko cần sửa đâu nhé!!!