4/9 < x < 9/4 |
Trả lời: x = ..............
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\(2+\dfrac{1}{2}-\dfrac{4}{3}+\left(-\dfrac{1}{3}\right)^4\)
=\(2+\dfrac{1}{2}-\dfrac{4}{3}+\dfrac{1}{81}\)
=\(\dfrac{5}{2}-\dfrac{4}{3}+\dfrac{1}{81}\)
=\(\dfrac{7}{6}+\dfrac{1}{81}\)
=\(\dfrac{191}{162}\)
\(2+\dfrac{1}{2}-\dfrac{4}{3}+\left(-\dfrac{1}{3}\right)^4\)
\(=\dfrac{5}{2}-\dfrac{4}{3}+\dfrac{1}{81}\)
\(=\dfrac{5}{2}-\dfrac{108}{81}+\dfrac{1}{81}\)
\(=\dfrac{5}{2}-\dfrac{107}{81}\)
\(=\dfrac{405}{162}-\dfrac{214}{162}=\dfrac{191}{162}\)
\(\dfrac{3}{5}+\dfrac{1}{6}.\dfrac{3}{4}=\dfrac{3}{5}+\dfrac{1}{8}=\dfrac{29}{40}\)
=> 3x . 31 + 3x . 32 = 92 . 4
=> 3x . ( 31 + 32 ) = 81.4
=> 3x . 12 = 324
=> 3x = 324 : 12
=> 3x = 27
=> 3x = 33
=> x = 3
`!`
\(a,\dfrac{8}{9}\times\dfrac{7}{5}-\dfrac{7}{9}\times\dfrac{2}{5}+\dfrac{2}{9}\\ =\dfrac{8}{9}\times\left(\dfrac{7}{5}-\dfrac{2}{5}\right)+\dfrac{2}{9}\\ =\dfrac{8}{9}\times\dfrac{5}{5}+\dfrac{2}{9}\\ =\dfrac{8}{9}+\dfrac{2}{9}\\ =\dfrac{10}{9}\)
\(b,\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{3}{12}\\ =\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{1}{4}\\ =\dfrac{1}{4}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)\\ =\dfrac{1}{4}\times\dfrac{9}{9}\\ =\dfrac{1}{4}\)
9.2=18
9.3=27
9.4=36
9.5=45
9.6=54
9.7=63
9.8=72
9.9=81
9.10=90
T mik nhé
x:5=9 ( dư 2 )
x=9x5+2
x=47
x:6=9 ( dư 5 )
x=9x6+5
x=59
x:8=4 ( dư 1 )
x=4x8+1
x=33
x : 5 = 9 ( dư 2 ) = 9 x 5 + 2 = 47
x : 6 = 9 ( dư 5 ) = 6 x 9 + 5 = 62
x : 8 = 4 ( dư 1 ) = 8 x 4 + 1 = 33
hok tốt
ĐỂ \(Ix-4I+I4-xI+Ix-9I=0\)\(\Leftrightarrow\hept{\begin{cases}x-4=0\\4-x=0\\x-9=0\end{cases}}\)
\(=>\hept{\begin{cases}x=4\\x=4\\x=9\end{cases}}\)
Mà x không thể đồng thời thỏa mãn ( x=4 hoặc x=9) => k có giá trị x thỏa mãn
Vi tri tuyet doi luon luon > hoac bang 0
Nen ta co
x-4+4-x+2x-18=0
=>2x=18
x=9
vì 4/9 < 1 nên 9/4 lớn hơn 2
vậy x = 2
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