X x 6 - 5138 =970 x 4
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : x * 6 = 5138 = 970 * 4
=> x = 5138 : 6
=> x = \(\frac{5138}{6}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
cái này của lớp 4 mà =.=",mà lớp 4 chưa học dấu âm và số thập phân
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x-971}{972}+\frac{x-973}{970}+\frac{x-975}{968}+\frac{x-977}{966}=\frac{x-972}{971}+\frac{x-970}{973}+\frac{x-968}{975}+\frac{x-966}{977}\)
\(\Rightarrow\frac{x-971}{972}-1+\frac{x-973}{970}-1+\frac{x-975}{968}-1+\frac{x-977}{966}-1=\frac{x-972}{971}-1+\frac{x-970}{973}-1+\frac{x-968}{975}-1+\frac{x-966}{977}-1\)\(\Rightarrow\frac{x-1943}{972}+\frac{x-1943}{970}+\frac{x-1943}{968}+\frac{x-1943}{966}=\frac{x-1943}{971}+\frac{x-1943}{973}+\frac{x-1943}{975}+\frac{x-966}{977}\)
\(\Leftrightarrow\frac{x-1943}{972}+\frac{x-1943}{970}+\frac{x-1943}{968}+\frac{x-1943}{966}-\frac{x-1943}{971}-\frac{x-1943}{973}-\frac{x-1943}{975}-\frac{x-966}{977}=0\)
\(\Leftrightarrow\left(x-1943\right).\left(\frac{1}{972}+\frac{1}{970}+\frac{1}{968}+\frac{1}{966}-\frac{1}{971}-\frac{1}{973}+\frac{1}{975}+\frac{1}{977}\right)=0\)
\(\Leftrightarrow\left(x-1943\right)=0\Leftrightarrow x=1943\)
Vậy...
![](https://rs.olm.vn/images/avt/0.png?1311)
970 - 10x = 1874
10x = 970 - 1874
10x = (- 904)
x = (-904) : 10
x = (-90,4)
![](https://rs.olm.vn/images/avt/0.png?1311)
Áp dụng tính chất dãy tỉ số bằng nhau, ta có:
\(x:y:z=5:3:4=\frac{x}{5}=\frac{y}{3}=\frac{z}{4}=\frac{x+2y-z}{5+6-4}=-\frac{121}{7}\)
\(\frac{x}{5}=-\frac{121}{7}.5=-\frac{605}{7}\)
\(\frac{y}{3}=-\frac{121}{7}.3=-\frac{363}{7}\)
\(\frac{z}{4}=-\frac{121}{7}.4=-\frac{484}{7}\)
Vậy x = \(-\frac{605}{7};y=-\frac{363}{7};z=-\frac{484}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
970 - x + x + x + x + x + x + x + x + x + x = 1840
\(\Rightarrow970-x+\left(x+x+x+x+x+x+x+x+x\right)=\) \(1840\)
\(\Rightarrow970-x+9x=1840\)
\(\Rightarrow970+8x=1840\)
\(\Rightarrow8x=1840-970\)
\(\Rightarrow8x=870\)
\(\Rightarrow x=108,75\)
Ta có :
970 - x + x + x + x + x + x + x + x + x + x = 1840
⇒970−x+(x+x+x+x+x+x+x+x+x)= 1840
⇒970−x+9x=1840
⇒970+8x=1840
⇒8x=1840−970
⇒8x=870
⇒x=108,75
![](https://rs.olm.vn/images/avt/0.png?1311)
a, Ta có : \(x:y:z=5:3:4\Rightarrow\frac{x}{5}=\frac{y}{3}=\frac{z}{4}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có :
\(\frac{x}{5}=\frac{y}{3}=\frac{z}{4}=\frac{x+2y-z}{5+6-4}=-\frac{126}{7}=-18\)
\(x=-90;y=-54;z=-72\)
b, \(5x=2y;3y=5z\Rightarrow\frac{x}{2}=\frac{y}{5};\frac{y}{5}=\frac{z}{3}\Rightarrow\frac{x}{2}=\frac{y}{5}=\frac{z}{3}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có :
\(\frac{x}{2}=\frac{y}{5}=\frac{z}{3}=\frac{x+y+z}{2+5+3}=-\frac{970}{10}=-97\)
\(x=-194;y=-485;z=-291\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) ta co: x\5=y\3=z\4 va x+2y-z=-121
Dat: x\5=y\3=z\4=k.suy ra: x=5k;y=3k;z=4k
=5k+2.(3k)-4k
=5k+6k-4k
=7k=-121
=-121:7k=-121\7
suy ra:x\5=-121\7suy ra: -121\7.5=-605\7
y\3=-121\7 suy ra:-121\7.3=-363\7
z\4=-121\7 suy ra:-121\7.3=-484\7
X x6-5138=970x4
Xx6-5138=3880
X x6 =3880+5138
X x 6 =9018
X =9018:6
X =1503
X x 6 - 5138 = 970 x 4
X x 6 - 5138 = 3880
X x 6 = 3880 + 5138
X x 6 = 9018
X = 9018 : 6
X = 1503