\(a\left(b^2+c^2\right)+b\left(c^2+a^2\right)+c\left(a^2+b^2\right)-2abc-a^3-b^3-c^3\)
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=\left(a+b-c\right)\left(a-b\right)^2\) nha !
P/S:Ko có mục đích xấu,đăng lên cho bạn thôi.
![](https://rs.olm.vn/images/avt/0.png?1311)
a(b2+c2)+b(c2+a2)+c(a2+b2)+22abc
= ab2+ac2+bc2+a2b+(a2c+b2c+2abc)
= ab(a+b)+c2(a+b)+c(a+b)2
= (a+b)(ab+c2+ac+bc)
= (a+b)[a(b+c)+c(b+c)
= (a+b)(b+c)(a+c)
b)
(a+b)(a2-b2)+(b+c)(b2-c2)+(a+c)(c2-a2)
= (a+b)(a2-b2)-(b+c)[(a2-b2)+(c2-a2)] +(a+c)(c2-a2)
= (a2-b2)(a+b-b-c) +(c2-a2)(a+c-b-c)
= (a2-b2)(a-c)+(c2-a2)(a-b)
= (a-b)(a2-ac+ab-bc +c2-a2)
= (a-b)[a(b-c)-c(b-c)]
= (a-b)(b-c)(a-c)
\(a^3\left(c-b^2\right)+b^3\left(a-c^2\right)+c^3\left(b-a^2\right)+abc\left(abc-1\right)\\ =a^3\left(c-b^2\right)+ab^3-b^3c^2+bc^3-a^2c^3+a^2b^2c^2-abc\\ =a^3\left(c-b^2\right)+bc^2\left(c-b^2\right)-ab\left(c-b^2\right)-a^2c^2\left(c-b^2\right)\\ =\left(c-b^2\right)\left(a^3+bc^2-ab-a^2c^2\right)\\ =\left(c-b^2\right)\left[a^2\left(a-c^2\right)-b\left(a-c^2\right)\right]\\ =\left(c-b^2\right)\left(a-c^2\right)\left(a^2-b\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(=ab\left(a+b\right)-bc\left(b+a\right)-bc\left(c-a\right)-ac\left(c-a\right)\)
\(=\left(a+b\right)\left(ab-bc\right)+\left(a-c\right)\left(bc-ac\right)\)
\(=\left(a+b\right)\cdot b\left(a-c\right)+\left(a-c\right)\cdot c\left(b-a\right)\)
\(=\left(a-c\right)\left(ab+b^2+cb-ac\right)\)
b: \(=ab^2+ac^2+bc^2+a^2b+a^2c+b^2c+2abc\)
\(=ab\left(a+b\right)+c^2\left(a+b\right)+c\left(a+b\right)^2\)
\(=\left(a+b\right)\left(ab+c^2+ac+cb\right)\)
\(=\left(a+b\right)\left(b+c\right)\left(a+c\right)\)
d: \(=a^3\left(b-c\right)-b^3\left(b-c+a-b\right)+c^3\left(a-b\right)\)
\(=a^3\left(b-c\right)-b^3\left(b-c\right)-b^3\left(a-b\right)+c^3\left(a-b\right)\)
\(=\left(b-c\right)\left(a-b\right)\left(a^2+ab+b^2\right)-\left(a-b\right)\left(b-c\right)\left(b^2+bc+c^2\right)\)
\(=\left(a-b\right)\left(b-c\right)\left(a^2+ab+b^2-b^2-bc-c^2\right)\)
\(=\left(a-b\right)\left(b-c\right)\left(a^2+ab-bc-c^2\right)\)
\(=\left(a-b\right)\left(b-c\right)\cdot\left[\left(a-c\right)\left(a+c\right)+b\left(a-c\right)\right]\)
\(=\left(a-b\right)\left(b-c\right)\left(a-c\right)\left(a+b+c\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a\left(b+c\right)^2\left(b-c\right)+b\left(c+a\right)^2\left(c-2\right)+c\left(a+b\right)^2\left(a-b\right)\)
\(=\left(b-c\right)\left(c-a\right)\left(c-b\right)\left(c+b+a\right)\)
nguồn câu hỏi tương tự
Trang 136 trong nâng cao phát triển có viết rồi mình cóp nó vô để mọi người dễ đọc nhé !
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a\left(b^2+c^2\right)+b\left(c^2+a^2\right)+c\left(a^2+b^2\right)+2abc\)
\(=ab^2+ac^2+bc^2+ba^2+c\left(a^2+b^2+2ab\right)\)
\(=ab\left(a+b\right)+c^2\left(a+b\right)+c\left(a+b\right)^2\)
\(=\left(a+b\right)\left(ab+c^2+ac+bc\right)\)
\(=\left(a+b\right)\left(a+c\right)\left(b+c\right)\)
\(a^3\left(b-c\right)+b^3\left(c-a\right)+c^3\left(a-b\right)\)
\(=a^3b-a^3c+b^3c-b^3a+c^3a-c^3b\)
\(=ab\left(a^2-b^2\right)-c\left(a^3-b^3\right)+c^3\left(a-b\right)\)
\(=ab\left(a+b\right)\left(a-b\right)-c\left(a^2+ab+b^2\right)\left(a-b\right)+c^3\left(a-b\right)\)
\(=\left(a-b\right)\left(a^2b+ab^2-a^2c-abc-b^2c+c^3\right)\)
\(=\left(a-b\right)\left[a^2\left(b-c\right)+ab\left(b-c\right)-c\left(b-c\right)\left(b+c\right)\right]\)
\(=\left(a-b\right)\left(b-c\right)\left(a^2+ab-bc-c^2\right)\)
\(=\left(a-b\right)\left(b-c\right)\left(a-c\right)\left(a+b+c\right)\)
a. \(a\left(b^2+c^2\right)+b\left(c^2+a^2\right)+c\left(a^2+b^2\right)+2abc\)
\(=ab^2+ac^2+bc^2+ba^2+\left(ca^2+cb^2+2abc\right)\)
\(ab\left(a+b\right)+c^2\left(a+b\right)+c\left(a+b\right)^2\)
\(=\left(a+b\right)\left(ab+c^2+ac+bc\right)=\left(a+b\right)\left(b+c\right)\left(c+a\right)\)
b. \(a^3\left(b-c\right)+b^3\left(c-a\right)+c^3\left(a-b\right)\)
Tách c - a thành \(-[\left(b-a\right)+\left(a-b\right)]:\)
\(a^3\left(b-c\right)-b^3[\left(b-c\right)+\left(a-b\right)]+c^3\left(a-b\right)\)
\(=a^3\left(b-c\right)-b^3\left(b-c\right)-b^3\left(a-b\right)+c^3\left(a-b\right)\)
\(=\left(b-c\right)\left(a^3+b^3\right)-\left(a-b\right)\left(b^3-c^3\right)\)
\(=\left(a-b\right)\left(a-c\right)\left(b-c\right)\left(a+b+c\right)\)