|x-1/2005|=5/9
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a, \(\frac{4}{7}x\frac{5}{7}+\frac{3}{7}x\frac{5}{6}\)
= ( \(\frac{4}{7}+\frac{3}{7}\)) x \(\frac{5}{7}x\frac{5}{6}\)
= 1 x \(\frac{5}{7}x\frac{5}{6}\)
= \(\frac{5}{7}x\frac{5}{6}\)
= \(\frac{25}{42}\)
Tương tự mấy câu sau cũng làm như thế này
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a)=(3/8+10/16)+(7/12+10/24)
=1+1=2
c)=(4/6+14/6)+(7/13+19/13)+(17/9+1/9)
=3+2+2=7
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\(\dfrac{x+1}{2013}+\dfrac{x+5}{2009}+\dfrac{x+9}{2005}>-3\)
\(\Leftrightarrow\)\(\dfrac{x+2014}{2013}+\dfrac{x+2014}{2009}+\dfrac{x+2014}{2005}>0\)
\(\Leftrightarrow\)(x+2014)(\(\dfrac{1}{2013}+\dfrac{1}{2009}+\dfrac{1}{2005}\))>0
Vì \(\dfrac{1}{2013}+\dfrac{1}{2009}+\dfrac{1}{2005}>0\) nên x+2014>0
\(\Leftrightarrow\)x>-2014
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\(\frac{4}{7}\times\frac{5}{6}+\frac{4}{7}\times\frac{1}{6}\)
\(=\frac{4}{7}\times\left(\frac{5}{6}+\frac{1}{6}\right)\)
\(=\frac{4}{7}\times1\)
\(=\frac{4}{7}\)
\(\frac{7}{9}\times\frac{8}{5}-\frac{7}{9}\times\frac{3}{5}\)
\(=\frac{7}{9}\times\left(\frac{8}{5}-\frac{3}{5}\right)\)
\(=\frac{7}{9}\times1\)
\(=\frac{7}{9}\)
\(\frac{3}{5}\times\frac{7}{9}-\frac{3}{5}\times\frac{2}{9}\)
\(=\frac{3}{5}\times\left(\frac{7}{9}-\frac{2}{9}\right)\)
\(=\frac{3}{5}\times\frac{5}{9}\)
\(=\frac{1}{3}\)
\(\frac{2}{5}\times\frac{3}{4}\times\frac{3}{5}=\frac{3}{10}\times\frac{3}{5}=\frac{9}{50}\)
\(\frac{5}{9}\times\frac{1}{4}+\frac{4}{9}\times\frac{3}{12}\)
\(=\frac{5}{9}\times\frac{1}{4}+\frac{4}{9}\times\frac{1}{4}\)
\(=\frac{1}{4}\times\left(\frac{5}{9}+\frac{4}{9}\right)\)
\(=\frac{1}{4}\times1\)
\(=\frac{1}{4}\)
\(\frac{2006}{2005}\times\frac{3}{4}-\frac{3}{4}\times\frac{1}{2005}\)
\(=\frac{3}{4}\times\left(\frac{2006}{2005}-\frac{1}{2005}\right)\)
\(=\frac{3}{4}\times1\)
\(=\frac{3}{4}\)
|x-1/2005|=5/9
x-1/2005 =5/9 hoặc x-1/2005= -5/9
x=..... x=........
sorry nhác tính