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a) 2/5+9/5=11/5
b) 15/45+25/30=7/6
c) 28/32+45/72=3/2
d) 8/28+5/30=19/42
bài 2
a) x - 4/5 =4/5 + (3/7+3/5)
x-4/5=4/5+36/35
x-4/5=64/35
x=64/35+4/5
x=92/35
b) x-7/35=4/5
x=4/5+7/35
x=1
nhớ tk m nhé
a = 18/5
b = 3/9 + 5/6 = 6/18 + 25/18 = 31/18
c = 7/8 + 5/8 = 12/8
d = 4/14 + 1/6 = 14/42 + 7/42 = 21/42 -= 7/14
b2
x - 4/5 = 4.5 + ( 3/7 + 3/5 )
x - 4/5 = 49/35
x = 49/35 + 4/5
x = 77/35
x - 7/35 = 4/5
x = 4/5 + 7/35
x = 1
mình ko chắc chắn đâu
mình nghĩ mình làm sai
Bài 1:
a: \(\sqrt{50}+2\sqrt{8}-\dfrac{3}{2}\cdot\sqrt{72}+\sqrt{125}\)
\(=5\sqrt{2}+2\cdot2\sqrt{2}-\dfrac{3}{2}\cdot6\sqrt{2}+\sqrt{125}\)
\(=9\sqrt{2}-9\sqrt{2}+5\sqrt{5}=5\sqrt{5}\)
b: \(\left(3\sqrt{2}-\sqrt{5}\right)^2-\dfrac{9}{\sqrt{5}-\sqrt{2}}\)
\(=18-2\cdot3\sqrt{2}\cdot\sqrt{5}+5-\dfrac{9\left(\sqrt{5}+\sqrt{2}\right)}{5-2}\)
\(=23-6\sqrt{10}-3\left(\sqrt{5}+\sqrt{2}\right)\)
\(=23-6\sqrt{10}-3\sqrt{5}-3\sqrt{2}\)
c: \(5\sqrt{4a}-3\sqrt{25a}+\sqrt{9a}\)
\(=5\cdot2\sqrt{a}-3\cdot5\sqrt{a}+3\sqrt{a}\)
\(=10\sqrt{a}-15\sqrt{a}+3\sqrt{a}=-2\sqrt{a}\)
a)25/50 + 5/15 = 1/2 + 1/3 = 5/6
b)72/90 + 7/28 = 4/5 + 1/4 =\(1\frac{1}{20}\)
c)32/96 + 8/28 = 1/3 + 2/7 = 13/21
Chúc bạn tết vui vẻ nha!
\(\frac{25}{50}+\frac{5}{15}=\frac{1}{2}+\frac{1}{3}=\frac{3}{6}+\frac{2}{6}=\frac{5}{6}\)
\(\frac{72}{90}+\frac{7}{28}=\frac{8}{10}+\frac{1}{4}=\frac{32}{40}+\frac{10}{40}=\frac{42}{40}=\frac{21}{20}\)
\(\frac{32}{96}+\frac{8}{28}=\frac{1}{3}+\frac{2}{7}=\frac{7}{21}+\frac{6}{21}=\frac{13}{21}\)
a, \(\frac{25}{50}\)= \(\frac{25:25}{50:25}\)= \(\frac{1}{2}\) \(\frac{5}{15}\)= \(\frac{5:5}{15:5}\)= \(\frac{1}{3}\)
\(\frac{1}{2}\)+ \(\frac{1}{3}\)= \(\frac{3}{6}\)+ \(\frac{2}{6}\)= \(\frac{5}{6}\)
b, \(\frac{72}{90}\)= \(\frac{72:18}{90:18}\)= \(\frac{4}{5}\) \(\frac{7}{28}\)= \(\frac{7:7}{28:7}\)= \(\frac{1}{4}\)
\(\frac{4}{5}\)+ \(\frac{1}{4}\) = \(\frac{16}{20}\)+ \(\frac{5}{20}\)= \(\frac{21}{20}\)
c, \(\frac{32}{96}\)= \(\frac{32:32}{96:32}\)= \(\frac{1}{3}\) \(\frac{8}{28}\)= \(\frac{8:4}{28:4}\)= \(\frac{2}{7}\)
\(\frac{1}{3}\)+ \(\frac{2}{7}\) = \(\frac{7}{21}\)+ \(\frac{6}{21}\)= \(\frac{13}{21}\)
Lời giải và hướng dẫn:
a) 25/50 + 5/15 = 1/2 + 1/3 = 3/6 + 2/6 = 5/6.
b) 72/90 + 7/28 = 4/5 + 1/4 = 16/20 + 5/20 = 21/20.
c) 32/96 + 8/28 = 1/3 + 2/7 = 7/21 + 6/21 = 13/21.
A)\(\frac{25}{50}+\frac{5}{15}\)
\(=\frac{1}{2}+\frac{1}{3}\)
\(=\frac{3+2}{6}\)\(=\frac{5}{6}\)
B) \(\frac{72}{90}+\frac{7}{28}\)\(=\frac{4}{5}+\frac{1}{4}\)\(=\frac{16+5}{20}\)\(=\frac{21}{20}\)
C)\(\frac{32}{96}+\frac{8}{28}\)\(=\frac{1}{3}+\frac{2}{7}\)\(=\frac{7+6}{21}\)=\(\frac{13}{21}\)
NĂM MỚI VUI VẺ
a) 66 - 60 = 6 98 - 90 = 8 72 - 70 = 2
78 - 50 = 28 59 - 30 = 29 43 - 20 = 23
b) 58 - 4 = 54 67 - 7 = 60 99 - 1 = 98
58 - 8 = 50 67 - 5 = 62 99 - 9 = 90
a) 66 - 60 = 6 98 - 90 = 8 72 - 70 = 2
78 - 50 = 28 59 - 30 = 29 43 - 20 = 23
b) 58 - 4 = 54 67 - 7 = 60 99 - 1 = 98
58 - 8 = 50 67 - 5 = 62 99 - 9 = 90
\(1,\)
\(a,\sqrt{6-2\sqrt{5}}=\sqrt{\sqrt{5^2}-2.\sqrt{5}.1+1}=\sqrt{\left(\sqrt{5}-1\right)^2}=\left|\sqrt{5}-1\right|=\sqrt{5}-1\)
\(b,\sqrt{8+2\sqrt{7}}=\sqrt{\sqrt{7^2}+2.\sqrt{7}.1+1}=\sqrt{\left(\sqrt{7}+1\right)^2}=\left|\sqrt{7}+1\right|=\sqrt{7}+1\)
\(2,\)
\(a,\sqrt{\left(\sqrt{10}-3\right)^2}-\sqrt{10}\)
\(=\left|\sqrt{10}-3\right|-\sqrt{10}\)
\(=\sqrt{10}-\sqrt{10}-3\)
\(=-3\)
\(b,\sqrt{\left(5+\sqrt{7}\right)^2}-\sqrt{8-2\sqrt{7}}\)
\(=\left|5+\sqrt{7}\right|-\sqrt{\left(\sqrt{7}-1\right)^2}\)
\(=5+\sqrt{7}-\left|\sqrt{7}-1\right|\)
\(=5+\sqrt{7}-\sqrt{7}+1\)
\(=6\)
a: \(=\left(\sqrt{3}-2\right)\cdot\sqrt{\left(2+\sqrt{3}\right)^2}\)
\(=\left(\sqrt{3}-2\right)\left(\sqrt{3}+2\right)\)
=3-4=-1
b: \(=\sqrt{6+4\sqrt{2}}-\sqrt{11-2\sqrt{18}}\)
\(=\sqrt{\left(2+\sqrt{2}\right)^2}-\sqrt{\left(3-\sqrt{2}\right)^2}\)
\(=2+\sqrt{2}-3+\sqrt{2}=2\sqrt{2}-1\)
c: \(=\sqrt{\left(2\sqrt{5}-1\right)^2}+\sqrt{\left(2\sqrt{5}+1\right)^2}\)
\(=2\sqrt{5}-1+2\sqrt{5}+1\)
\(=4\sqrt{5}\)
Nhanh lên giúp tớ