A=9/1.4+9/4.7+...+9/91.94
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9A = 1.4.[7+2] + 4.7. [10-1] + 7.10.[13-4] +...+ 91.94. [97-88]
= 1.4.7 + 1.2.4 + 4.7.10 - 1.4.7 + 7.10.13 - 4.7.10+...+ 91.94.97 - 88.91.94
= 1.2.4 + 91.94.97 = 8 +829738 = 829746 => A = 829746 : 9 = 92194
đúng cái nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
\(B=\dfrac{9}{1\cdot4}+\dfrac{9}{4\cdot7}+...+\dfrac{9}{97\cdot100}\)
\(B=3\cdot\left(\dfrac{3}{1\cdot4}+\dfrac{3}{7\cdot10}+...+\dfrac{3}{97\cdot100}\right)\)
\(B=3\cdot\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+...+\dfrac{1}{97}-\dfrac{1}{100}\right)\)
\(B=3\cdot\left(1-\dfrac{1}{100}\right)\)
\(B=3\cdot\left(\dfrac{100}{100}-\dfrac{1}{100}\right)\)
\(B=3\cdot\dfrac{99}{100}\)
\(B=\dfrac{297}{100}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)\(\frac{2}{1.4}+\frac{2}{4.7}+\frac{2}{7.10}+...+\frac{2}{91.94}+\frac{2}{94.97}\)
=\(\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{91}-\frac{1}{94}+\frac{1}{94}-\frac{1}{97}\)(giản ước các phân số giống nhau)
=\(\frac{1}{1}-\frac{1}{97}\)
=\(\frac{96}{97}\)
a) gọi \(A=\frac{2}{1.4}+\frac{2}{4.7}+\frac{2}{7.11}+...+\frac{2}{94.97}\)
\(\Rightarrow\frac{3}{2}A=\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{94.97}\)
\(\frac{3}{2}A=\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{94}-\frac{1}{97}\)(rút gọn các phân số giống nhau)
\(\frac{3}{2}A=\frac{1}{1}-\frac{1}{97}\)
\(\frac{3}{2}A=\frac{96}{97}\left(1\right)\)
từ \(\left(1\right)\Leftrightarrow A=\frac{96}{97}\div\frac{3}{2}=\frac{64}{97}\)
b)\(\left(1-\frac{1}{7}\right).\left(1-\frac{1}{8}\right).\left(1-\frac{1}{9}\right).....\left(1-\frac{1}{2011}\right)\)
\(=\frac{6}{7}.\frac{7}{8}.\frac{8}{9}......\frac{2010}{2011}\)
\(=\frac{6.7.8.9.....2010}{7.8.9......2011}\)(rút gọn các số giống nhau)
\(=\frac{6}{2011}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3}{1.4}+\frac{3}{4.7}+.....+\frac{3}{94.97}\)
\(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+.........+\frac{1}{94}-\frac{1}{97}\)
\(=1-\frac{1}{97}\)
\(=\frac{96}{97}\)
mà \(\frac{96}{97}< 1\)
\(\Rightarrow\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{94.07}< 1\)
vậy..................
\(\frac{3}{1\cdot4}+\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+...+\frac{3}{91\cdot94}+\frac{3}{94\cdot97}\)
\(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{94}-\frac{1}{97}\)
\(=1-\frac{1}{97}\)
\(=\frac{96}{97}\)
\(\Rightarrow\frac{96}{97}< 1\)
\(\Rightarrow\frac{3}{1\cdot4}+\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+...+\frac{3}{94\cdot97}< 1\)
Vậy \(\frac{3}{1\cdot4}+\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+...+\frac{3}{94\cdot97}< 1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{9}{1.4}+\frac{9}{4.7}+...+\frac{9}{53.56}\)
\(\Rightarrow\frac{1}{3}A=\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{53.56}\)
\(\Rightarrow\frac{1}{3}A=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{53}-\frac{1}{56}\)
\(\Rightarrow\frac{1}{3}A=1-\frac{1}{56}\)
\(\Rightarrow\frac{1}{3}A=\frac{55}{56}\)
\(\Rightarrow A=\frac{55}{56}\times3\)
\(\Rightarrow A=\frac{165}{56}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{94.97}\)
\(\Leftrightarrow1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{94}-\frac{1}{97}\)
\(\Leftrightarrow1-\frac{1}{97}=\frac{96}{97}\)
Do \(\frac{96}{97}< 1\Rightarrow\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{94.97}< 1\)
Vậy:.............................<1
![](https://rs.olm.vn/images/avt/0.png?1311)
Đặt 2/3 ra ngoài trong ngoặc còn :
1-1/4+1/4-1/7+...-1/97=96/97
Lấy 2/3 nhân với 96/97 sẽ ra đáp án nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{1}{1\cdot4}+\frac{1}{4\cdot7}+...+\frac{1}{91\cdot94}=\frac{1}{3}\left(\frac{3}{1\cdot4}+\frac{3}{4\cdot7}+...+\frac{3}{91\cdot94}\right)\)
\(=\frac{1}{3}\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{91}-\frac{1}{94}\right)\)
\(=\frac{1}{3}\left[\left(1-\frac{1}{94}\right)+\left(\frac{1}{4}-\frac{1}{4}\right)+...+\left(\frac{1}{91}-\frac{1}{91}\right)\right]\)
\(=\frac{1}{3}\left[\left(\frac{94}{94}-\frac{1}{94}\right)+0+...+0\right]=\frac{1}{3}\cdot\frac{93}{94}=\frac{93}{282}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{3}{1.4}\) + \(\dfrac{3}{4.7}\) + ... + \(\dfrac{3}{91.94}\)
= 1 - \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\) - \(\dfrac{1}{7}\) + ... + \(\dfrac{1}{91}\) - \(\dfrac{1}{94}\)
= 1 - \(\dfrac{1}{94}\)
= \(\dfrac{93}{94}\)
\(\dfrac{3}{1.4}+\dfrac{3}{4.7}+....+\dfrac{3}{94.97}\)
= \(3.\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+....+\dfrac{1}{94}-\dfrac{1}{97}\right)\)
= \(3.\left(1-\dfrac{1}{97}\right)\)
= \(3.\dfrac{96}{97}\)
= \(\dfrac{288}{97}\)
\(\frac{A}{3}=\frac{4-1}{1.4}+\frac{7-4}{4.7}+...+\frac{91-91}{91.94}\)
\(\frac{A}{3}=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{91}-\frac{1}{94}=1-\frac{1}{94}=\frac{93}{94}\Rightarrow A=\frac{3.93}{94}\)