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27 + 4/3 27 - 4/3
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NT
1
12 tháng 12 2017
\(3\frac{4}{27}.30,3-3\frac{4}{27}.9,3-3\frac{4}{27}.3\)
\(=3\frac{4}{27}.\left(30,3-9,3-3\right)\)
\(=3\frac{4}{27}.18\)
\(=\frac{170}{3}\)
KY
1
VH
5
VH
2
L
11 tháng 5 2020
Trả lời :
\(a,\frac{3}{2}\times\left(\frac{5}{7}-\frac{4}{3}\right)-\frac{4}{3}\times\left(\frac{5}{7}-\frac{3}{2}\right)\)
\(=\frac{3}{2}\times\frac{5}{7}-\frac{3}{2}\times\frac{4}{3}-\frac{4}{3}\times\frac{5}{7}+\frac{4}{3}\times\frac{3}{2}\)
\(=\frac{3}{2}\times\frac{5}{7}-\frac{4}{3}\times\frac{5}{7}\)
\(=\frac{5}{7}\times\left(\frac{3}{2}-\frac{4}{3}\right)\)
\(=\frac{5}{42}\)
b, Tương tự câu a. Kết quả \(=-\frac{3}{7}\)
PT
1
CM
6 tháng 6 2018
a. x × 3 = 27
x = 27 : 3
x = 9
b. 4 × x = 20
x = 20 : 4
x = 5
c. 10 + x : 2 = 20
x : 2 = 20 – 10
x : 2 = 10
x = 10 × 2
x = 20
d. x × 3 = 27 + 3
x × 3 = 30
x = 30 : 3
x = 10
e. 27 : x = 789 – 780
27 : x = 9
x = 27 : 9
x = 3
VN
Võ Ngọc Phương
CTVHS
VIP
1 tháng 10 2023
\(\left(3-x\right)^3=-\dfrac{27}{64}\)
\(\left(3-x\right)^3=\left(\dfrac{-3}{4}\right)^3\)
\(=>3-x=\dfrac{-3}{4}\)
\(x=3-\dfrac{-3}{4}=\dfrac{12}{4}+\dfrac{3}{4}\)
\(x=\dfrac{15}{4}\)
________
\(\left(x-5\right)^3=\dfrac{1}{-27}\)
\(\left(x-5\right)^3=\left(\dfrac{-1}{3}\right)^3\)
\(=>x-5=\dfrac{-1}{3}\)
\(x=\dfrac{-1}{3}+5=\dfrac{-1}{3}+\dfrac{15}{3}\)
\(x=\dfrac{14}{3}\)
_____________
\(\left(x-\dfrac{1}{2}\right)^3=\dfrac{27}{8}\)
\(\left(x-\dfrac{1}{2}\right)^3=\left(\dfrac{3}{2}\right)^3\)
\(=>x-\dfrac{1}{2}=\dfrac{3}{2}\)
\(x=\dfrac{3}{2}+\dfrac{1}{2}\)
\(x=2\)
________
\(\left(2x-1\right)^2=\dfrac{1}{4}\)
\(\left(2x-1\right)^2=\left(\dfrac{1}{2}\right)^2\) hoặc \(\left(2x-1\right)^2=\left(\dfrac{-1}{2}\right)^2\)
\(=>2x-1=\dfrac{1}{2}\) \(2x-1=\dfrac{-1}{2}\)
\(2x=\dfrac{1}{2}+1=\dfrac{1}{2}+\dfrac{2}{2}\) \(2x=\dfrac{-1}{2}+1=\dfrac{-1}{2}+\dfrac{2}{2}\)
\(2x=\dfrac{3}{2}\) \(2x=\dfrac{1}{2}\)
\(x=\dfrac{3}{2}:2=\dfrac{3}{2}.\dfrac{1}{2}\) \(x=\dfrac{1}{2}:2=\dfrac{1}{2}.\dfrac{1}{2}\)
\(x=\dfrac{3}{4}\) \(x=\dfrac{1}{4}\)
____________
\(\left(2-3x\right)^2=\dfrac{9}{4}\)
\(\left(2-3x\right)^2=\left(\dfrac{3}{2}\right)^2\) hoặc \(\left(2-3x\right)^2=\left(\dfrac{-3}{2}\right)^2\)
\(=>2-3x=\dfrac{3}{2}\) \(2-3x=\dfrac{-3}{2}\)
\(3x=2-\dfrac{3}{2}=\dfrac{4}{2}-\dfrac{3}{2}\) \(3x=2-\dfrac{-3}{2}=\dfrac{4}{2}+\dfrac{3}{2}\)
\(3x=\dfrac{1}{2}\) \(3x=\dfrac{7}{2}\)
\(x=\dfrac{1}{2}.\dfrac{1}{3}\) \(x=\dfrac{7}{2}.\dfrac{1}{3}\)
\(x=\dfrac{1}{6}\) \(x=\dfrac{7}{6}\)
______________
\(\left(1-\dfrac{2}{3}\right)^2=\dfrac{4}{9}\) -> Kiểm tra đề câu này
1 tháng 10 2023
(3-x)3=(-\(\dfrac{3}{4}\))3
3-x=-\(\dfrac{3}{4}\)
x=3-(-\(\dfrac{3}{4}\))
x=\(\dfrac{15}{4}\)
27+4/3=81/3+4/3=85/3
27-4/3=81/3-4/3=77/3