a)154+75-38^0
b)35-(3.5^2-2.4^2)
Giải giúp tui
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\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}.,,\frac{50^2}{49.51}\)
=\(\frac{2.2}{1.3}.\frac{3.3}{2.4}.\frac{4.4}{3.5}.,,\frac{50.50}{49.51}\)
=\(\frac{\left(2.3.4...50\right).\left(2.3.4...50\right)}{\left(1.2.3....49\right).\left(3.4.5....51\right)}\)
=\(\frac{50.2}{1.51}\)
=\(\frac{100}{51}\)
\(=\frac{2.3.4...50}{1.2.3...49}.\frac{2.3.4...50}{3.4.5...51}=50.\frac{2}{51}=\frac{100}{51}\)
b) 3.25.8+ 4.37.6+2.38.12
= 24.25+24.37+24.38
=24.(25+ 37+38)
=24.100
=2400
c) (563+745)-(463+545)
= (563-463)+(745+545)
= 100 + 100
= 200
a) 35 x 34 + 35 x 38 + 65 x 75 + 65 x 45
= 35 x (34+38) + 65 x (75 + 45)
= 35 x 72 + 65 x 120
= 2520 + 7800 = 10320
b) 3 x 25 x 8 + 4 x 37 x 6 + 2 x 38 x 12
= 3 x ( 25 x 8) + 4 x (37 x 6) + 2 x (38 x 12)
= 3 x 200 + 4 x 222 + 2 x 456
= 600 + 888 + 912 = 2400
tk nha
35 x 34 + 35 x 38 + 65 x 75 + 65 x 45
= 35 x ( 34 + 38 ) + 65 x ( 45 + 75 )
= 35 x 72 + 65 x 120
`a)(2x-1)^2-0,25=0`
`<=>(2x-1-0,5)(2x-1+0,5)=0`
`<=>(2x-1,5)(2x-0,5)=0`
`<=>[(x=0,75)(x=0,25):}`
`b)x^2+9=6x`
`<=>(x-3)^2=0`
`<=>x-3=0`
`<=>x=3`
`c)(x^2-4)-3x-6=0`
`<=>(x-2)(x+2)-3(x+2)=0`
`<=>(x+2)(x-2-3)=0`
`<=>(x+2)(x-5)=0`
`<=>[(x=-2),(x=5):}`
a: =>(2x-1-0,5)(2x-1+0,5)=0
=>(2x-1,5)(2x-0,5)=0
=>x=0,25 hoặc x=0,75
b: =>x^2-6x+9=0
=>(x-3)^2=0
=>x-3=0
=>x=3
c: =>(x-2)(x+2)-3(x+2)=0
=>(x+2)(x-5)=0
=>x=5 hoặc x=-2
Bài 1:
uses crt;
var i,s:integer;
begin
clrscr;
s:=0;
for i:=10 to 50 do
if i mod 2=0 then s:=s+i;
writeln(s);
readln;
end.
Bài 2:
uses crt;
var a,i,n:integer;
begin
clrscr;
write('Nhap n='); readln(n);
a:=0;
for i:=1 to n do
a:=a+i*(i+2);
writeln(a);
readln;
end.
a, 35.(34+86) + 65.(75+45)
=35.120 + 65.120
=120.(35+65)
=120. 100
=12000
a) 35 * 34 + 35 * 86 + 65 * 75 + 65 * 45
= 35 x ( 34 + 86 ) x 65 x ( 75 + 45 )
= 35 x 120 x 65 x 120
= 120 x ( 35 + 65 )
= 120 x 100
= 12000
a) 154+75-380
= 154+75-1
= 228
b) 35-(3.52-2.42)
= 35-(3.25-2.16)
= 35-(75-32)
= 35-43
= -8