x phần 27 = -2 phần 3,6
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\(\frac{x}{2,7}=\frac{-2}{3,6}\)
\(\Rightarrow x3,6=\left(-2\right).2,7\)
\(\Rightarrow x3,6=-5,4\)
\(\Rightarrow x=\frac{-5,4}{3,6}\)
\(\Rightarrow x=\frac{-3}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: \(\dfrac{-3}{5}x+\dfrac{-7}{4}=\dfrac{3}{10}\)
\(\Leftrightarrow\dfrac{-3}{5}x=\dfrac{3}{10}+\dfrac{7}{4}=\dfrac{41}{20}\)
\(\Leftrightarrow x=\dfrac{41}{20}:\dfrac{-3}{5}=\dfrac{41}{20}\cdot\dfrac{-5}{3}\)
hay \(x=-\dfrac{41}{12}\)
Vậy: \(x=-\dfrac{41}{12}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
x +\(\frac{3}{2}\)X \(\frac{3}{2}\)=\(\frac{27}{4}\)
x +\(\frac{3}{2}\) = \(\frac{27}{4}\):\(\frac{3}{2}\)
x +\(\frac{3}{2}\) = \(\frac{54}{12}\)=\(\frac{18}{4}\)=\(\frac{9}{2}\)
x =\(\frac{9}{2}\)-\(\frac{3}{2}\)
x =\(\frac{7}{2}\)
CHÚC BẠN HỌC TỐT
\(x+\frac{3}{2}\times\frac{3}{2}=\frac{27}{4}\)
\(x+\frac{9}{4}=\frac{27}{4}\)
\(x=\frac{27}{4}-\frac{9}{4}\)
\(x=\frac{18}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{25}{27}:\frac{4}{7}+\frac{2}{27}:\frac{4}{7}\)
\(=\frac{4}{7}\left(\frac{25}{27}+\frac{2}{27}\right)\)
\(=\frac{4}{7}.1\)
\(=\frac{4}{7}\)
| x - 1 | = \(\frac{4}{5}\)
\(\Rightarrow\orbr{\begin{cases}\left|x-1\right|=\frac{4}{5}\\\left|x-1\right|=\frac{-4}{5}\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{9}{5}\\x=\frac{1}{5}\end{cases}}}\)
\(\frac{25}{27}:\frac{4}{7}+\frac{2}{27}:\frac{4}{7}\)
= \(\left(\frac{25}{27}+\frac{2}{27}\right):\frac{4}{7}\)
=\(1:\frac{4}{7}=\frac{7}{4}\)\(=1\frac{3}{4}\)
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\(\frac{3,64:5}{10}+1,18\times4+3,6:0,25\)
\(=0,0728+4,72+14,4\)
\(=4,7928+14,4\)
\(=19,1928\)