giúgiúp mik ik
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Bài trên:
\(16x^3y+0,25yz^3=\dfrac{1}{4}y\left(64x^3+z^3\right)=\dfrac{1}{4}y\left[\left(4x\right)^3+z^3\right]\\ =\dfrac{1}{4}y\left[\left(4x+z\right)\left(16x^2-4xz+z^2\right)\right]\\ ----\\ x^4-4x^3+4x^2=x^2\left(x^2-4x+4\right)=x^2\left(x-2\right)^2\\ -----\\ a^3+a^2b-ab^2-b^3=\left(a^3-b^3\right)+\left(a^2b-ab^2\right)\\ =\left(a-b\right)\left(a^2+ab+b^2\right)+ab\left(a-b\right)=\left(a-b\right)\left(a^2+2ab+b^2\right)=\left(a-b\right)\left(a+b\right)^2\)
Bài trên
\(x^3+x^2-4x-4\\ =x^2\left(x+1\right)-4\left(x+1\right)\\ =\left(x^2-4\right)\left(x+1\right)\\ =\left(x-2\right)\left(x+2\right)\left(x+1\right)\\ ---\\ x^3-x^2-x+1\\ =x^2\left(x-1\right)-\left(x-1\right)\\ =\left(x^2-1\right)\left(x-1\right)\\ =\left(x-1\right)\left(x+1\right)\left(x-1\right)=\left(x-1\right)^2\left(x+1\right)\\ ---\\ x^4+x^3+x^2-1\\ =x^3\left(x+1\right)+\left(x-1\right)\left(x+1\right)\\ =\left(x^3+x-1\right)\left(x+1\right)\\ ---\\ x^2y^2+1-x^2-y^2\\ =x^2.\left(y^2-1\right)-\left(y^2-1\right)\\ =\left(y^2-1\right)\left(x^2-1\right)\\ =\left(y-1\right)\left(y+1\right)\left(x-1\right)\left(x+1\right)\)
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không đảng câu hỏi linh tinh
không sẽ bị khóa nick đó
ai đồng ý thì k mik nha
![](https://rs.olm.vn/images/avt/0.png?1311)
a: 0,6m=60cm
a/b=60/70=6/7
b: 0,2 tạ=20kg
a/b=20/12=5/3
c: 75cm=3/4
a/b=2/3:3/4=2/3*4/3=8/9
d: 3/10h=18p
=>a/b=18/20=9/10
![](https://rs.olm.vn/images/avt/0.png?1311)
đổi :12'=0,2h
s=v.t=0,2.8=1,6km
8km/h là giá trị vận tốc của học sinh đi từ nhà đến trường hết 12' chứ gì nx???
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\(a,\left(\dfrac{3}{5}+\dfrac{2}{5}\right)+\left(\dfrac{4}{7}+\dfrac{1}{7}+\dfrac{2}{7}\right)=1+1=2\)
\(b,\left(\dfrac{1}{3}+\dfrac{4}{3}+\dfrac{2}{3}\right)+\left(\dfrac{1}{6}+\dfrac{2}{6}+\dfrac{5}{6}\right)=\dfrac{7}{3}+\dfrac{4}{3}=\dfrac{11}{3}\)
a)\(\dfrac{3}{5}+\dfrac{4}{7}+\dfrac{2}{5}+\dfrac{1}{7}+\dfrac{2}{7}\)
\(=\left(\dfrac{3}{5}+\dfrac{2}{5}\right)+\left(\dfrac{4}{7}+\dfrac{1}{7}+\dfrac{2}{7}\right)\)
\(=1+1\)
\(=2\)
b)\(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{4}{3}+\dfrac{2}{6}+\dfrac{2}{3}+\dfrac{5}{6}\)
\(=\left(\dfrac{1}{3}+\dfrac{4}{3}+\dfrac{2}{3}\right)+\left(\dfrac{1}{6}+\dfrac{2}{6}+\dfrac{5}{6}\right)\)
\(=\dfrac{7}{3}+\dfrac{4}{3}\)
\(=\dfrac{11}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Điền vào đó từ four nha!
Four seasos in Hanoi