\(\frac{57}{300}\)
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![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\frac{57}{300}=\frac{19}{100}=19\%\)
\(b,\frac{24}{400}=\frac{6}{100}=6\%\)
\(c,\frac{12}{500}=\frac{2.4}{100}=2,4\%\)
\(d,\frac{750}{600}=\frac{125}{100}=125\%\)
~Study well~
#๖ۣۜNamiko#
GIẢI
a) \(\frac{57}{300}=\frac{19}{100}=19\%\)
b) \(\frac{24}{400}=\frac{6}{100}=6\%\)
c)\(\frac{12}{500}=\frac{6}{250}=2,4\%\)
d )\(\frac{750}{600}=\frac{125}{100}=125\%\)
P/S: HOK TỐT !
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=\frac{3.\left(\frac{1}{51}-\frac{4}{57}+\frac{11}{59}\right)}{5.\left(\frac{1}{51}-\frac{4}{57}+\frac{11}{59}\right)}=\frac{3.1}{5.1}=\frac{3}{5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(274+351+126-151\)
\(=274+126+351-151\)
=400+200
=600
b: \(5^7:5^5\cdot3\cdot7\cdot4\)
\(=5^2\cdot21\cdot4\)
\(=21\cdot100=2100\)
c: \(164\cdot27+164\cdot73-400\)
\(=164\left(27+73\right)-400\)
=16400-400
=16000
d: \(300-2\cdot\left[\left(6^2-32\right):2^2+99\right]\)
\(=300-2\left[\dfrac{\left(36-32\right)}{4}+99\right]\)
=300-200
=100
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
d) Ta có: \(-8+\left(-14\right)+34+\left(-12\right)\)
\(=-8-14+34-12\)
\(=-20+20\)
\(=-0\)
e) Ta có: \(\left(-7\right)+\left(-20\right)+57+\left(-30\right)\)
\(=\left(-7+57\right)+\left(-20-30\right)\)
\(=50-50=0\)
f) Ta có: \(300-\left(-180\right)-120-42\)
\(=300+180-120-42\)
\(=258+60=318\)
d, Ta có : \(\left(-8\right)+\left(-14\right)+34+\left(-12\right)\)
\(=-\left(8+12\right)+34-14=-20+20=0\)
e, Ta có : \(\left(-7\right)+\left(-20\right)+57+\left(-30\right)\)
\(=-\left(30+20\right)+57-7=-50+50=0\)
f, Ta có : \(300-\left(-180\right)-120-42=318\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : ''Phần hơn'' của \(\frac{7^{58}+2}{7^{57}+2}\) là :
\(\frac{7^{58}+2}{^{ }7^{57}+2}\) \(-\) 1 = \(\frac{7^{57}.6}{7^{57}+2}\)
''Phần hơn'' của \(\frac{5^{57}+2017}{5^{56}+2017}\) với 1 là :
\(\frac{7^{57}+2017}{7^{56}+2017}\) \(-\) 1 = \(\frac{7^{56}.6}{7^{56}+2017}\)
Ta có :\(\frac{7^{56}.6}{7^{56}+2017}\) = \(\frac{7^{56}.7.6}{\left(7^{56}+2017\right)7}\) = \(\frac{7^{57}.6}{7^{57}+14119}\)
Ta thấy \(\frac{7^{57}.6}{7^{57}+2}\)> \(\frac{7^{57}.6}{7^{57}+14119}\)
Suy ra \(\frac{7^{57}.6}{7^{57}+2}\) > \(\frac{7^{56}.6}{7^{56}+2017}\)
Do đó \(\frac{7^{58}+2}{7^{57}+2}\) > \(\frac{7^{57}+2017}{7^{56}+2017}\)
\(\frac{57}{300}=\frac{19}{100}\)
57/300 = 57 : 3 / 300 : 3 = 19/100