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![](https://rs.olm.vn/images/avt/0.png?1311)
a)5.(-8).2.(-3)
=[5.(-2)].[(-8).(-3)]
=-10.24
=-240
b)(45-135+72)-(45+72)
=45-135+72-45-72
=(45-45)+(72-72)-135
=0+0-135
=-135
c)3.(-5)2.2+2.(-5)-20
=3.25.2+2(-5)-20
=75.2+(-10)-20
=150+(-30)
=120
d)86.(-46)+46.27-46.41
=86.(-1).46+46.27-46.41
=-86.46+46.27-46.41
=46(-86+27-41)
=46(-100)
-4600
e)34(15-10)-15(34-10)
=34.15-34.10-15.34+15.10
=(34.15-15.34)+(15.10-34.10)
=[34(15-15)]+[10(15-34)]
=34.0+10(-9)
=0+(-90)
=-90
![](https://rs.olm.vn/images/avt/0.png?1311)
5 - 10 + 15 - 20 + 25 - ... - 300 + 305
= (5 + 305) - (10 + 300) + (15 + 295) - ... + (145 + 165) - (150 + 160) + 155
= 155
Cứ gộp nhóm vào sao cho trong ngoặc đó bằng 310 còn dấu thì theo thứ tự đề bài ra
~ Học tốt ~
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(3.5^2+15.2^2-26\div2\)
= 3.25 + 15.4 - 13
= 75 + 60 - 13
= 135 - 13
= 122
b) \(5^3.2-100\div4+2^3.5\)
= 125.2 - 25 + 8.5
= 250 - 25 + 40
= 225 + 40
= 265
c)\(6^2\div9+50.2-3^3.33\)
= 36 : 9 + 100 - 9.33
= 4 + 100 - 297
= 104 - 297
= -193
d)\(3^2.5+2^3.10-81\div3\)
= 9.5 + 8.10 - 27
= 45 + 80 - 27
= 125 - 27
= 98
e) \(5^{13}\div5^{10}-25.2^2\)
= 53 - 25.4
= 125 - 100
= 25
f) \(20\div2^2+5^9\div5^8\)
= 20 : 4 + 5
= 5 + 5
= 10
![](https://rs.olm.vn/images/avt/0.png?1311)
`1/2+2/4+3/6+4/8+5/10+6/12`
`=1/2+1/2+1/2+1/2+1/2+1/2`
`=1/2*6=3`
`1/3+1/4+1/5+8/10+20/15+20/30`
`=(1/3+1/4)+(1/5+4/5)+(4/3+2/3)`
`=7/12+1+2`
`=7/12+3=43/12`
\(\dfrac{1}{2}+\dfrac{2}{4}+\dfrac{3}{6}+\dfrac{4}{8}+\dfrac{5}{10}+\dfrac{6}{12}\)
\(=\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{1}{2}\)
\(=\dfrac{1}{2}\times6=3\)
\(------\)
\(\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{8}{10}+\dfrac{20}{15}+\dfrac{20}{30}\)
\(=\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{4}{5}+\dfrac{4}{3}+\dfrac{2}{3}\)
\(=\left(\dfrac{1}{3}+\dfrac{4}{3}+\dfrac{2}{3}\right)+\left(\dfrac{1}{5}+\dfrac{4}{5}\right)+\dfrac{1}{4}\)
\(=\dfrac{7}{3}+1+\dfrac{1}{4}\)
\(=\dfrac{28}{12}+\dfrac{12}{12}+\dfrac{3}{12}\)
\(=\dfrac{43}{12}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(N=\frac{1}{1.5}+\frac{1}{5.10}+\frac{1}{10.15}+\frac{1}{15.20}+...+\frac{1}{2005.2010}\)
\(=\frac{1}{5}+\frac{1}{5}\left(\frac{5}{5.10}+\frac{5}{10.15}+...+\frac{5}{2005.2010}\right)\)
\(=\frac{1}{5}+\frac{1}{5}\left(\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+...+\frac{1}{2005}-\frac{1}{2010}\right)\)
\(=\frac{1}{5}+\frac{1}{5}\left(\frac{1}{5}-\frac{1}{2010}\right)\)
\(=\frac{1}{5}+\frac{1}{5}.\frac{410}{2010}\)
\(=\frac{1}{5}+\frac{401}{10050}\)
Tự tính tiếp hị rồi rút gọn ra
bn chịu khó dịch bởi vì mk ko thuận viết bằng PHÂN SỐ lắm , mong bn thông cảm
N= 1/1*5 + 1/5*10 + 1/10*15 + ... + 1/2005*2010
N = 1- 1/5 + 1/5 - 1/10 + ... + 1/2005 - 1/2010
N = \(1-\frac{1}{2010}=\frac{2010}{2010}-\frac{1}{2010}\)
N = \(\frac{2009}{2010}\)
Đây là bài làm của mk
chúc bn học tốt !
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 5 x (-8) x 2 x (-3)
= (5 x 2 ) x [(-8)x(-3)]
= 10 x 24
= 240
b) 3 x (-5)2 + 2 x ( -5 ) - 20
= 3 x 25 - 2 x 5 - 2 x 10
= 7.5 x 10 - 10 - 2 x 10
= ( 7.5 - 1 - 2 ) x 10
= 4.5 x 10
= 45
c) 34 x ( 15 - 10 ) - 15 ( 34 - 10 )
= [ 34 x 15 - 34 x 10 ] - [ 15 x 34 - 15 x 10 ]
= 34 x 15 - 34 x 10 - 15 x 34 + 15 x 10
= ( 34 x 15 - 15 x 34 ) - ( 34 x 10 - 15 x 10 )
= 0 - 10 ( 34 - 15 )
= 0 - 10 x 19
= -190
Tính nhanh
a) 5.(-8).2.(-3)
= (5 . 2) . [(-8) . (-3)]
= 10 . 24
= 240
![](https://rs.olm.vn/images/avt/0.png?1311)
-1980 đúng k?
1980
HOk tot