Tính:
11 10 - 2 5 : 2 3
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\(2\dfrac{1}{3}.3=\dfrac{7}{3}.3=7.\\ \left(\dfrac{2}{5}-\dfrac{3}{4}\right)-\dfrac{2}{5}=\dfrac{2}{5}-\dfrac{3}{4}-\dfrac{2}{5}=-\dfrac{3}{4}.\\ \dfrac{-10}{11}.\dfrac{4}{7}+\dfrac{-10}{11}.\dfrac{3}{7}+1\dfrac{10}{11}.\\ =\dfrac{-10}{11}\left(\dfrac{4}{7}+\dfrac{3}{7}-1\right).\\ =\dfrac{-10}{11}.\left(1-1\right)=0.\)
1) 2\(\dfrac{1}{3}\).3=\(\dfrac{7}{3}\).3=7.
2) (2/5 -3/4) -2/5 = 2/5 -3/4 -2/5 = -3/4.
3) \(\dfrac{-10}{11}.\dfrac{4}{7}+\dfrac{-10}{11}.\dfrac{3}{7}+1\dfrac{10}{11}=\dfrac{1}{11}\left(-\dfrac{40}{7}-\dfrac{30}{7}+21\right)=\dfrac{1}{11}.\left(-10+21\right)=1\).
\(a,A=\dfrac{\dfrac{5}{4}+\dfrac{5}{5}+\dfrac{5}{7}-\dfrac{5}{11}}{\dfrac{10}{4}+\dfrac{10}{5}+\dfrac{10}{7}-\dfrac{10}{11}}\\ =\dfrac{5.\left(\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{1}{7}-\dfrac{1}{11}\right)}{10.\left(\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{1}{7}-\dfrac{1}{11}\right)}\\ =\dfrac{5}{10}\\ =\dfrac{1}{2}\)
Vậy \(A=\dfrac{1}{2}\)
\(b,B=\dfrac{2+\dfrac{6}{5}-\dfrac{6}{7}-\dfrac{6}{11}}{\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{7}-\dfrac{2}{11}}\\ =\dfrac{3.\left(\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{7}-\dfrac{2}{11}\right)}{\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{7}-\dfrac{2}{11}}\\ =3\)
Vậy \(B=3\)
a: Ta có: \(\left(2^2\cdot5\cdot3^3-5^2\cdot2^3+20\right)\cdot3^2-10\)
\(=\left(4\cdot5\cdot27-25\cdot8+20\right)\cdot9-10\)
\(=\left(540-200+20\right)\cdot9-10\)
\(=3240-10=3230\)
1: =72/90+65/90=137/90
2: =24/56-77/56=-53/56
3: =-7/10+4/5=1/10
4: =15/100-4/100=11/100
5: =4/6-5/6=-1/6
6: =10/40-15/40-76/40=-81/40
7: =-9/10+7/18
=-81/90+35/90=-46/90=-23/45
8: =27/90-55/90=-28/90=-14/45
9: =36/60-50/60-35/60=-49/60
10: =-4/9+5/6-3/8
=-32/72+60/72-27/72
=1/72
Q=(2^9.3+2^9.5):2^12
Đặt A=2^9.3+2^9.5
A=2^9.(3+5)
A=2^9.8
Mặt khác:8=2^3
=>A=2^9.2^3
A=2^12
Theo đề bài ta có Q=(2^9.3+2^9.5):2^12
=>Q=2^12:2^12
Q=1
Nhìn dài dòng thế thôi chứ đơn giản lắm.Nếu thấy đúng thì cho mình nhé!
`[3^10 .11+3^10 .5]/[3^9 . 2^4]`
`=[3^9(3.11+3.5)]/[3^9 . 2^4]`
`=[33+15]/16=48/16=3`
`(3^10 .11 + 3^10 . 5)/(3^9 . 2^4)`.
`<=> (3^10 . (11+5))/(3^9. 2^4)`
`<=> (3^10 . 16)/(3^9. 2^4)`.
`<=> (3^10 . 2^4)/(3^9 . 2^4)`
`<=> 3.`
\(\dfrac{3^{10}.11+3^{10}.5}{3^9.2^4}\)=\(\dfrac{3^{10}.\left(11+5\right)}{3^9.2^4}\)=\(\dfrac{3.16}{2^4}\)=\(\dfrac{3.2^4}{2^4}\)=3
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