1+2+3+4+5...+123+124+125
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TM
1
TM
8 tháng 7 2015
(1/2+2/3+3/4+4/5+...+122/123+123/124).(125-5.25)
=(1/2+2/3+3/4+4/5+...+122/123+123/124).(125-125)
=(1/2+2/3+3/4+4/5+...+122/123+123/124).0=0
WT
Phep so sanh nao dung?
A. 123/124 > 124/125
B. 123/124=124/125
C. 123/124<124/125
D. 123/124 = 124-1/125
2
AN
2
25 tháng 5 2018
\(\frac{x+1}{125}+\frac{x+2}{124}+\frac{x+3}{123}+\frac{x+4}{122}+\frac{x+146}{5}=0\)
\(\left(\frac{x+1}{125}+1\right)+\left(\frac{x+2}{124}+1\right)+\left(\frac{x+3}{123}+1\right)+\left(\frac{x+4}{122}+1\right)+\left(\frac{x+146}{5}-4\right)=0\)
\(\frac{x+126}{125}+\frac{x+126}{124}+\frac{x+126}{123}+\frac{x+126}{122}+\frac{x+126}{5}=0\)
\(\left(x+126\right).\left(\frac{1}{125}+\frac{1}{124}+\frac{1}{123}+\frac{1}{122}+\frac{1}{5}\right)=0\)
vì \(\left(\frac{1}{125}+\frac{1}{124}+\frac{1}{123}+\frac{1}{122}+\frac{1}{5}\right)\ne0\)nên x + 126 = 0 \(\Rightarrow\)x = -126
XO
18 tháng 8 2020
a) Vì \(721< 834\Rightarrow\frac{5}{721}>\frac{5}{834}\)
b) Ta có \(\frac{4}{37}< \frac{5}{37}< \frac{5}{36}\Rightarrow\frac{4}{37}< \frac{5}{36}\)
c) Ta có \(\frac{1994}{1995}=1-\frac{1}{1995}\)
\(\frac{1999}{2000}=1-\frac{1}{2000}\)
Vì \(\frac{1}{1995}>\frac{1}{2000}\Rightarrow1-\frac{1}{1995}< 1-\frac{1}{2000}\Rightarrow\frac{1994}{1995}< \frac{1999}{2000}\)
d) Ta có :\(\frac{489}{487}=1+\frac{2}{487}\)
\(\frac{487}{485}=1+\frac{2}{485}\)
Vì \(\frac{2}{485}>\frac{2}{487}\Rightarrow1+\frac{2}{485}>1+\frac{2}{487}\Rightarrow\frac{489}{487}>\frac{487}{485}\)
e) Ta có : \(\frac{123.125+119}{124.125-177}=\frac{123.125+119}{\left(123+1\right).125-177}=\frac{123.125+119}{123.125+125-177}=\frac{123.125+119}{123.125-52}\)
\(=\frac{123.125-52+171}{123.125-52}=1+\frac{171}{123.125-52}>1\)
f) \(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{199.200}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{199}-\frac{1}{200}=1-\frac{1}{200}< 1\)
NN
1
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
18 tháng 8 2023
A = \(\dfrac{3^{123}+1}{3^{125}+1}\) Vì 3123 + 1 < 2125 + 1 Nên A = \(\dfrac{3^{123}+1}{3^{125}+1}\)< \(\dfrac{3^{123}+1+2}{3^{125}+1+2}\)
A < \(\dfrac{3^{123}+3}{3^{125}+3}\) = \(\dfrac{3.\left(3^{122}+1\right)}{3.\left(3^{124}+1\right)}\) = \(\dfrac{3^{122}+1}{3^{124}+1}\) = B
Vậy A < B
LT
0
7875 tick giùm cái cho tròn 20
\(\frac{125\cdot\left(125+1\right)}{2}=7875\)