Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Ta có : \(\left(2^2:\frac{4}{3}-\frac{1}{2}\right).\frac{6}{5}-17\)
=\(=\left(4.\frac{3}{4}-\frac{1}{2}\right).\frac{6}{5}-17\)
\(=\frac{5}{2}.\frac{6}{5}-17\)
\(=3-17=-14\)
Tụi quá mới lớp 5 thui
a) \(2^3+3.\left(\frac{1}{2}\right)^0+\left[\left(-2\right)^2:\frac{1}{2}\right]\)
\(=8+3.1+4:\frac{1}{2}\)
\(=8+3+8=19\)
b)\(\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^3}=\frac{2^{15}.3^8}{2^6.3^6.2^9}\)\(=\frac{2^{15}.3^8}{2^{15}.3^6}=3^2=9\)
c) \(\left(1+\frac{2}{3}-\frac{1}{4}\right).\left(\frac{4}{5}-\frac{3}{4}\right)^2\)
\(=\frac{17}{12}.\frac{1}{400}=\frac{17}{4800}\)
d) \(\left(-\frac{10}{3}\right)^3.\left(\frac{-6}{5}\right)^4=-\frac{100}{27}.\frac{1296}{625}\)\(=\frac{-4.48}{1.25}=-\frac{192}{25}\)
Bài 2 :
\(a,\frac{3}{2}.\frac{4}{9}-\frac{1}{5}+\frac{2}{15}\)
\(=\frac{2}{3}-\frac{1}{5}+\frac{2}{15}\)
\(=\frac{10}{15}-\frac{3}{15}+\frac{2}{15}\)
\(=\frac{9}{15}=\frac{3}{5}\)
\(b,\left(\frac{1}{2}\right)^2.\frac{4}{3}+\frac{8}{5}:\frac{2}{5}\)
\(=\frac{1}{4}.\frac{4}{3}+\frac{8}{5}.\frac{5}{2}\)
\(=\frac{1}{3}+4\)
\(=\frac{13}{3}\)
\(c,\sqrt{196}-\sqrt{100}+\sqrt{\frac{9}{4}}\)
\(=14-10+\frac{3}{2}\)
\(=4+\frac{3}{2}\)
\(=\frac{11}{2}\)
Học tốt