Tìm x
\(x-\frac{3\left(x+30\right)}{15}-24\frac{1}{2}=\frac{7x}{10}-\frac{2\left(10x+2\right)}{5}\)
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VM
3 tháng 4 2020
\(x-\frac{3.\left(x+30\right)}{15}-24\frac{1}{2}=\frac{7x}{10}-\frac{2.\left(10x+2\right)}{5}\)
\(\Leftrightarrow\frac{x}{1}-\frac{3x+90}{15}-\frac{49}{2}=\frac{7x}{10}-\frac{20x+4}{5}\)
\(\Leftrightarrow\frac{30x}{30}-\frac{2.\left(3x+90\right)}{15.2}-\frac{49.15}{2.15}=\frac{7x.3}{10.3}-\frac{6.\left(20x+4\right)}{6.5}\)
\(\Leftrightarrow\frac{30x}{30}-\frac{6x+180}{30}-\frac{735}{30}=\frac{21x}{30}-\frac{120x+24}{30}\)
\(\Rightarrow30x-\left(6x+180\right)-735=21x-\left(120x+24\right)\)
\(\Leftrightarrow30x-6x-180-735=21x-120x-24\)
\(\Leftrightarrow24x-915=-99x-24\)
\(\Leftrightarrow24x+99x=-24+915\)
\(\Leftrightarrow123x=891\)
\(\Leftrightarrow x=891:123\)
\(\Leftrightarrow x=\frac{297}{41}.\)
Vậy phương trình có tập hợp nghiệm là: \(S=\left\{\frac{297}{41}\right\}.\)
Chúc bạn học tốt!
S
3 tháng 4 2020
x-\(\frac{3\left(x+30\right)}{15}\)-26=\(\frac{7x}{10}\)-\(\frac{2\left(10x+2\right)}{5}\)
➜\(\frac{30x}{30}\)-\(\frac{6\left(x+30\right)}{30}\)-\(\frac{780}{30}\)=\(\frac{21x}{30}\)-\(\frac{12\left(10x+2\right)}{30}\)
➜ 30x-6x-180-780=21x-120x-24
➜30x-6x-21x-120x=780+180-24
➜Bạn tự tính!!!
11 tháng 3 2020
1) \(\frac{7}{8}x-5\left(x-9\right)=\frac{20x+1,5}{6}\)
<=> \(\frac{21x}{24}-\frac{100\left(x-9\right)}{24}=\frac{80x+6}{24}\)
<=> 21x - 100x + 900 = 80x + 6
<=> -79x - 80x = 6 - 900
<=> -159x = -894
<=> x = 258/53
Vậy S = {258/53}
2) \(\frac{\left(2x+1\right)^2}{5}-\frac{\left(x+1\right)^2}{3}=\frac{7x^2-14x-5}{15}\)
<=> \(\frac{3\left(4x^2+4x+1\right)}{15}-\frac{5\left(x^2+2x+1\right)}{15}=\frac{7x^2-14x-5}{15}\)
<=> 12x2 + 12x + 3 - 5x2 - 10x - 5 = 7x2 - 14x - 5
<=> 7x2 + 2x - 7x2 + 14x = -5 + 2
<=> 16x = 3
<=> x = 3/16
Vậy S = {3/16}
11 tháng 3 2020
3) 4(3x - 2) - 3(x - 4) = 7x+ 10
<=> 12x - 8 - 3x + 12 = 7x + 10
<=> 9x - 7x = 10 - 4
<=> 2x = 6
<=> x = 3
Vậy S = {3}
4) \(\frac{\left(x+10\right)\left(x+4\right)}{12}-\frac{\left(x+4\right)\left(2-x\right)}{4}=\frac{\left(x+10\right)\left(x-2\right)}{3}\)
<=> \(\frac{x^2+14x+40}{12}+\frac{3\left(x^2+2x-8\right)}{12}=\frac{4\left(x^2+8x-20\right)}{12}\)
<=> x2 + 14x + 40 + 3x2 + 6x - 24 = 4x2 + 32x - 80
<=> 4x2 + 20x - 4x2 - 32x = -80 - 16
<=> -12x = -96
<=> x = 8
Vậy S = {8}
28 tháng 1 2017
a) \(\frac{x+\frac{2\left(3-x\right)}{5}}{14}-\frac{5x-4\left(x-1\right)}{24}=\frac{7x+2+\frac{9-3x}{5}}{12}+\frac{2}{3}\)
<=> \(\frac{5x+2\left(3-x\right)}{70}-\frac{5x-4\left(x-1\right)}{24}=\frac{35x+10+9-3x}{60}+\frac{2}{3}\)
<=> \(12\left(5x+6-2x\right)-35\left(5x-4x+4\right)\)
<=> \(14\left(35x+10+9-3x\right)+280.2\) <=> \(12\left(3x+6\right)-35\left(x+4\right)\)
<=> \(14\left(32x+19\right)+560\)
<=> \(36x+72-35x-140=448x+226+560\)
<=> \(-447x=894\)
<=> x = -2
8 tháng 1 2020
1.
\(\frac{2x+3}{4}-\frac{5x+3}{6}=\frac{3-4x}{12}\)
\(MC:12\)
Quy đồng :
\(\Rightarrow\frac{3.\left(2x+3\right)}{12}-\left(\frac{2.\left(5x+3\right)}{12}\right)=\frac{3x-4}{12}\)
\(\frac{6x+9}{12}-\left(\frac{10x+6}{12}\right)=\frac{3x-4}{12}\)
\(\Leftrightarrow6x+9-\left(10x+6\right)=3x-4\)
\(\Leftrightarrow6x+9-3x=-4-9+16\)
\(\Leftrightarrow-7x=3\)
\(\Leftrightarrow x=\frac{-3}{7}\)
2.\(\frac{3.\left(2x+1\right)}{4}-1=\frac{15x-1}{10}\)
\(MC:20\)
Quy đồng :
\(\frac{15.\left(2x+1\right)}{20}-\frac{20}{20}=\frac{2.\left(15x-1\right)}{20}\)
\(\Leftrightarrow15\left(2x+1\right)-20=2\left(15x-1\right)\)
\(\Leftrightarrow30x+15-20=15x-2\)
\(\Leftrightarrow15x=3\)
\(\Leftrightarrow x=\frac{3}{15}=\frac{1}{5}\)
4 tháng 6 2016
Tìm x, biết:
3(x+2)(x+5) +5(x+5)(x+10) +7(x+10)(x+17) =x(x+2)(x+17) (x∉−2;−5;−10;−17)
2(x−1)(x−3) +5(x−3)(x−8) +12(x−8)(x−20) −1x−20 =−34 (x∉1;3;8;20)
x+110 +2+111 x+112 =x+113 +x+114
x−1030 +x−1443 +x−595 +x−1488 =0