(2x+3)x(xy-4)=14
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a: =2(x-2)+y(x-2)
=(x-2)(2+y)
b: \(=\left(x+y\right)^2-4=\left(x+y+2\right)\left(x+y-2\right)\)
c: =(x-7)(x+2)
a.
2x - 4 + xy - 2y
= 2(x-2) +y(x-2)
= (x-2)(y+2)
c.
x^2 - 5x - 14
= x^2 + 2x - 7x - 14
= x(x+2) - 7(x+2)
= (x-7)(x+2)
![](https://rs.olm.vn/images/avt/0.png?1311)
a.
\(\left(x-y\right)\left(x^3+x^2y+xy^2+y^3\right)-x^4+y^4=x^4+x^3y+x^2y^2+xy^3-x^3y-x^2y^2-xy^3-y^4-x^4+y^4\)
\(=\left(x^4-x^4\right)+\left(y^4-y^4\right)+\left(x^3y-x^3y\right)+\left(xy^3-xy^3\right)+\left(x^2y^2-x^2y^2\right)=0\)
b.
\(\left(2-x\right)\left(1+2x\right)+\left(1+x\right)-\left(x^4+x^3-5x^2-5\right)=2+4x-x-2x^2+1+x-x^4-x^3+5x^2+5\)
\(=-x^4-x^3+\left(5x^2-2x^2\right)+\left(4x-x+x\right)+\left(1+2+5\right)=-x^4-x^3+3x^2+4x+8\)
c.
\(\left(x^2-7\right)\left(x+2\right)-\left(2x-1\right)\left(x-14\right)+x\left(x^2-2x-22\right)+35=x^3+2x^2-7x-14-2x^2+28x+x-14+x^3-2x^2-22x+35\)
\(=\left(x^3+x^3\right)+\left(2x^2-2x^2\right)+\left(28x-22x-7x+x\right)+\left(35-14\right)=2x^3+21\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Câu 1:
a: =>-2x-x+17=34+x-25
=>-3x+17=x+9
=>-4x=-8
hay x=2
b: =>17x+16x+27=2x+43
=>33x+27=2x+43
=>31x=16
hay x=16/31
c: =>-2x-3x+51=34+2x-50
=>-5x+51=2x-16
=>-7x=-67
hay x=67/7
e: 3x-32>-5x+1
=>8x>33
hay x>33/8
![](https://rs.olm.vn/images/avt/0.png?1311)
1.
x.y=-11
=> x,y thuộc Ư(-11)={-1,-11,1,11}
Ta có bảng :
x | -1 | -11 | 1 | 11 |
y | -11 | -1 | 11 | 1 |
Vậy ta có các cặp x,y thõa mãn là : (-1,-11);(-11,-1);(1,11);(11,1)
2) x(x-2)=0
\(\Rightarrow\orbr{\begin{cases}x=0\\x-2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=2\end{cases}}\)
Vậy x=0 hoặc x=2
3) (2x+1)y=-14
=> 2x+1 ; y thuộc Ư(-14)={-1,-2,-7,-14,1,2,7,14}
Ta có bảng :
2x+1 | -1 | -2 | -7 | -14 | 1 | 2 | 7 | 14 |
y | -14 | -7 | -2 | -1 | 14 | 7 | 2 | 1 |
x | -1 | -3/2 | -4 | -15/2 | 0 | 1/2 | 3 | 13/2 |
Vậy ...
4) (2y-1)x=-18
=> 2y-1 ; x thuộc Ư(-18)={-1,-2,-3,-6,-9,-18,1,2,3,6,9,18}
Ta có bảng :
2y-1 | -1 | -2 | -3 | -6 | -9 | -18 | 1 | 2 | 3 | 6 | 9 | 18 |
x | -18 | -9 | -6 | -3 | -2 | -1 | 18 | 9 | 6 | 3 | 2 | 1 |
y | 0 | -1/2 | -1 | -7/2 | -4 | -17/2 | 1 | 3/2 | 2 | 7/2 | 5 | 19/2 |
Vậy ...
![](https://rs.olm.vn/images/avt/0.png?1311)
1) 2x + 2y - x(x+y)
= 2(x + y) - x(x + y)
= (2 - x)(x + y)
2/ 5x2 - 5xy -10x + 10y
= 5x(x - y) - 10(x - y)
= (5x - 10(x - y)
3/ 4x2 + 8xy - 3x - 6y
= 4x(x + 2y) - 3(x + 2y)
= (4x - 3)(x + 2y)
1) 2x + 2y - x(x + y)
= 2(x + y) - x(x + y)
= (2 - x)(x + y)
2) 5x2 - 5xy - 10x + 10y
= 5x(x - y) - 10(x - y)
= (5x - 10)(x - y)
= 5(x - 2)(x - y)
3) 4x2 + 8xy - 3x - 6y
= 4x(x + 2y) - 3(x + 2y)
= (4x - 3)(x + 2y)
4) 2x2 + 2y2 - x2z + z - y2z - 2
= 2(x2 + y2 - z(x2 + y2) - (2 - z)
= (2 - z)(x2 + y2) - (2 - z)
= (2 - z)(x2 + y2)
5) x2 + xy - 5x - 5y
= x(x + y) - 5(x + y)
= (x - 5)(x + y)
6) x(2x - 7) - 4x + 14
= x(2x - 7) - 2(2x - 7)
= (x - 2)(2x - 7)
7)x2 - 3x + xy - 3y
= x(x + y) - 3(x + y)
= (x - 3)(x + y)
giải nhanh giùm mk nha