tìm x
x+0,2=11
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\(\dfrac{-12}{25}.\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)
\(\dfrac{3}{4}-x+\dfrac{-6}{11}-\dfrac{5}{6}=0\)
\(\dfrac{3}{4}-x+\dfrac{-91}{66}=0\)
\(\dfrac{3}{4}-x=0-\left(\dfrac{-91}{66}\right)\)
\(\dfrac{3}{4}-x=\dfrac{91}{66}\)
\(x=\dfrac{-83}{132}\)
\(x-\dfrac{3}{11}=\dfrac{9}{12}\Rightarrow x=\dfrac{9}{12}+\dfrac{3}{11}=\dfrac{45}{44}\)
⇒ \(x=\dfrac{23}{5}:\dfrac{8}{11}\)
⇒ \(x=\dfrac{253}{40}\)
\(x\left(x+1\right)-\left(x-2\right)=11\)
\(\Rightarrow x^2+x-x+2=11\)
\(\Rightarrow x^2+2=11\)
\(\Rightarrow x^2=11-2\)
\(\Rightarrow x^2=9\)
\(\Rightarrow x^2=3^2\)
\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
\(x:\dfrac{7}{11}=\dfrac{5}{7}\Leftrightarrow x=\dfrac{5}{7}.\dfrac{7}{11}=\dfrac{5}{11}\)
\(x+0,2=11\)
\(x=11-0,2\)
\(x=10,8\)
x+0,2=11
x =11-0,2
x =10,8