\(41\frac{38}{45}-\left(43\frac{38}{45}+\frac{17}{22}\right)\)
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a)
\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
= \(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)
= \(\frac{1}{3}+\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)
= \(\frac{1}{3}+\left(-1\right)+1\)
= \(\frac{1}{3}+0=\frac{1}{3}\)
b)
\(\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)
= \(\frac{38}{45}-\frac{8}{45}+\frac{17}{51}+\frac{3}{11}\)
= \(\left(\frac{38}{45}-\frac{8}{45}\right)+\left(\frac{17}{51}+\frac{3}{11}\right)\)
= \(\frac{2}{3}+\frac{20}{33}\)
= \(\frac{14}{11}\)
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=71+38/45- 43+8/45 +1+17/57
=(71 \(\frac{38}{45}-43\frac{8}{45}\))+ 1+17/57=28+2/3+1+17/57=29+55/57=29/55/57
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Trả lời
b)(1/3+12/67+13/41)-(79/67-28/41)
=1/3+12/67+13/41-79/67+28/41
=1/3+(12/67-79/67)+(13/41+28/41)
=1/3+(-67/67)+41/41
=1/3+(-1)+1
=1/3+0
=1/3.
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a) 31/23 - ( 7/32 + 8/22)
= 31/23 - 7/32 + 8/23
= ( 31/23 + 8/23 ) - 7/32
= 32/22 - 7/32
= 39/32
Ccá ý khác làm tương tự
\(41\frac{38}{45}-\left(43\frac{38}{45}+\frac{17}{22}\right)\)
\(=41\frac{38}{45}-43\frac{38}{45}-\frac{17}{22}\)
\(=\left(41-43\right)+\left(\frac{38}{45}-\frac{38}{45}\right)-\frac{17}{22}\)
\(=-2-\frac{17}{22}\)
\(=-2\frac{17}{22}\)