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Những câu hỏi liên quan
BH
1
DT
Đỗ Thanh Hải
CTVVIP
8 tháng 10 2021
1 How long do you live in HN
2 How often did you go to the movies
3 What did Mrs Robinson buy
4 When was your father in Nghe An
5 How do they go to school
6 Why didn't she go to class
7 Who left home at 7o'clock yesterday
8 What subject does he study in the high school
9 What is your favorite hobby
10 How far is it
ND
1
MN
24 tháng 8 2021
\(2xR+yO_2\underrightarrow{^{^{t^0}}}2R_xO_y\)
\(2KMnO_4+16HCl_{\left(đ\right)}\underrightarrow{^{^{t^0}}}2KCl+2MnCl_2+5Cl_2+8H_2O\)
\(C_nH_{2n+2}+\dfrac{3n+1}{2}O_2\underrightarrow{^{^{t^0}}}nCO_2+\left(n+1\right)H_2O\)
\(8Al+30HNO_3\rightarrow8Al\left(NO_3\right)_3+3N_2O+15H_2O\)
K
ai giúp mình vs mình đang cần gấp
0
TM
8 tháng 9 2021
a/ \(\left(x-3\right)^2+6\left(x-3\right)+9\)
\(=\left(x-3\right)^2+2.\left(x-3\right).3+3^2\)
\(=\left(x-3+3\right)^2=x^2\)
==========
b/ \(\left(x+2021\right)^2+2\left(x+2021\right)\left(x-2021\right)+\left(x-2021\right)^2\)
\(=\left(x+2021+x-2021\right)^2=4x^2\)
===========
c/ \(2022^2-2.2021.2022+2021^2\)
\(=\left(2022-2021\right)^2=1\)
==========
d/ \(\left(x+44\right)^2-88\left(x+44\right)+1936\)
\(=\left(x+44\right)^2-2.\left(x+44\right).44+44^2\)
\(=\left(x+44-44\right)^2=x^2\)
8 tháng 9 2021
d: Ta có: \(\left(x+44\right)^2-88\left(x+44\right)+1936\)
\(=\left(x+44-44\right)^2\)
\(=x^2\)
1, \(\sqrt{3x-6}=3\)đk : x >= 2
\(\Leftrightarrow3x-6=9\Leftrightarrow x=5\)
3, \(\sqrt{2x+1}=\sqrt{x}\)đk : \(\hept{\begin{cases}x\ge-\frac{1}{2}\\x\ge0\end{cases}}\Leftrightarrow x\ge0\)
\(\Leftrightarrow2x+1=x\Leftrightarrow x=-1\)( loại )
5, \(\sqrt{4\left(x+2\right)^2}=8\Leftrightarrow2\left|x+2\right|=8\Leftrightarrow\left|x+2\right|=4\)
TH1 : \(x+2=4\Leftrightarrow x=2\)
TH2 : \(x+2=-4\Leftrightarrow x=-6\)
7, \(\sqrt{x-1}=2-x\)đk : \(\hept{\begin{cases}x-1\ge0\\2-x\ge0\end{cases}}\Leftrightarrow\hept{\begin{cases}x\ge1\\x\le2\end{cases}}\Leftrightarrow1\le x\le2\)
\(\Leftrightarrow x-1=x^2-4x+4\Leftrightarrow x^2-5x+5=0\)
\(\Leftrightarrow x_1=\frac{5+\sqrt{5}}{2}\left(ktm\right);x_2=\frac{5-\sqrt{5}}{2}\left(tm\right)\)