\(5x-3y=2xy-11\\ \Rightarrow10x-6y=4xy-22\\ \Rightarrow10x-6y-4xy+22=0\\ \Rightarrow\left(10x-4xy\right)+\left(15-6y\right)+7=0\\ \Rightarrow2x\left(5-2y\right)+3\left(5-2y\right)=-7\\ \Rightarrow\left(2x+3\right)\left(5-2y\right)=-7\)
Rồi lâp bảng xét ước ra nha em !!
\(\Leftrightarrow\left(2x+3;-2y+5\right)\in\left\{\left(1;-7\right);\left(-7;1\right);\left(-1;7\right);\left(7;-1\right)\right\}\)
hay \(\left(x,y\right)\in\left\{\left(-1;6\right);\left(-5;2\right);\left(-2;-1\right);\left(2;2\right)\right\}\)