16.17-5/16.16+11 = ?
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28 tháng 3 2018
\(\frac{16.17-5}{16.16+11}=\frac{16.\left(16+1\right)-5}{16.16+11}=\frac{16.16+16-5}{16.16+11}=\frac{16.16+11}{16.16+11}=1\)
XO
14 tháng 7 2019
\(\frac{16.17-5}{16.16+11}\)
= \(\frac{16.\left(16+1\right)-5}{16.16}\)
= \(\frac{16.16+16-5}{16.16+11}\)
= \(\frac{16.16+11}{16.16+11}\)
= \(1\)
14 tháng 7 2019
\(\frac{16.17-5}{16.16+11}=\frac{17-5}{16+11}=\frac{8}{27}\)
Hok tốt ~~
K chắc đâu
# DanLinh
20 tháng 8 2017
Ta có: \(\dfrac{16.17-5}{16.16+11}\)= \(\dfrac{16.\left(16+1\right)-5}{16.16+11}\)
= \(\dfrac{16.16+16-5}{16.16+11}\)= \(\dfrac{16.16+11}{16.16+11}\)= 1
DH
20 tháng 8 2017
\(\dfrac{16.17-5}{16.16+11}\) = \(\dfrac{16.\left(16+1\right)-5}{16.16+11}\) = \(\dfrac{16.16+16-5}{16.16+11}\) =\(\dfrac{16.16+11}{16.16+11}=1\)
9 tháng 7 2018
a) \(100:17+53:17=\left(100+53\right):17=153:17=9\)
b) \(1895:5-1745:5=\left(1895-1745\right):5=150:5=30\)
c) \(\left(864.48-432.96\right):\left(864.48.432\right)\)
\(=\left(864.48-432.2.48\right):\left(864.48.432\right)\)
\(=\left(864.48-864.48\right):\left(864.48.432\right)\)
\(=0:\left(864.48.432\right)\)
\(=0\)
d) \(\left(16.17-5\right):\left(16.16+11\right)\)
\(=\left[16.\left(16+1\right)-5\right]:\left(16.16+11\right)\)
\(=\left[16.16+16-5\right]:\left(16.16+11\right)\)
\(=\left[16.16+11\right]:\left(16.16+11\right)\)
\(=1\)
_Chúc bạn học tốt_
28 tháng 6 2018
a) \(\frac{16.17-5}{16.16+11}=\frac{16.16+16-5}{16.16+11}=\frac{16.16+11}{16.16+11}=1\)1
b ) \(\frac{5}{30}+\frac{15}{90}+\frac{25}{150}+\frac{35}{210}+\frac{45}{270}=\frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}\)
\(=\frac{1}{6}.5=\frac{5}{6}\)
28 tháng 6 2018
a) (16x17-5)/(16x16+11)=(16x16-5+16)/(16x16+11)=1
b) (1x5)/(6x5)+(3x5)/(18x5)+...+(9x5)/(54x5)
=1/6+1/6+1/6+1/6+1/6
=5/6
7 tháng 7 2018
a, (195 . 132 - 132 . 85) : 110
\(=132\left(195-85\right):110\)
\(=132.110:110\)
\(=132\)
NT
26 tháng 3 2018
a) \(\left(56.27+56.35\right):62\)
\(=56.\left(27+35\right):62\)
\(=56.62:62\)
\(=56\)
b) \(3\frac{2}{7}.12\frac{1}{2}-3\frac{2}{7}.5\frac{1}{2}+1\frac{1}{2}:\frac{3}{4}\)
\(=3\frac{2}{7}.\left(12\frac{1}{2}-5\frac{1}{2}\right)+\frac{3}{2}.\frac{4}{3}\)
\(=\frac{23}{7}.7+2\)
\(=23+2\)
\(=25\)
c) \(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.\left(16+1\right)-5}{16.16+11}\)
\(=\frac{16.16+16-5}{16.16+11}\)
\(=\frac{16.16+11}{16.16+11}\)
\(=1\)
\(\frac{16.17-5}{16.16+11}=\frac{16.16+16-5}{16.16+11}=\frac{16.16+11}{16.16+11}=1\)