Tính nhannh:
c, \(\frac{5.27^3.4^5}{6^5}:(\frac{5^5.2^4}{10^4}.\frac{2^6.3^4}{6^4})\)
d, \(\frac{5-\frac{5}{3}-\frac{5}{9}-\frac{5}{27}}{8-\frac{8}{3}-\frac{8}{9}-\frac{8}{27}}\frac{15-\frac{15}{11}+\frac{15}{121}}{16-\frac{16}{11}-\frac{16}{121}}\)
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C = \(\dfrac{\dfrac{1}{9}-\dfrac{5}{6}-4}{\dfrac{7}{12}-\dfrac{1}{36}-10}\)
C = \(\dfrac{\dfrac{6-45-216}{54}}{\dfrac{21-1-360}{36}}\)
C = \(\dfrac{\dfrac{-85}{18}}{-\dfrac{85}{9}}\)
C = \(\dfrac{1}{2}\)
1/ \(\frac{9.5^{20}.27^9-3.9^{15}.25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\)
\(=\frac{5^{20}.3^{29}-3^{31}.5^{18}}{7.3^{29}.5^{18}-3^{29}.5^{19}}=\frac{3^{29}.5^{18}.\left(25-9\right)}{3^{29}.5^{18}.\left(7-5\right)}=\frac{16}{2}=8\)
CÁC BÀI CÒN LẠI TƯƠNG TỰ HẾT NHÉ E
\(\frac{5-\frac{5}{3}+\frac{5}{9}-\frac{5}{27}}{8-\frac{8}{3}+\frac{8}{9}-\frac{8}{27}}:\frac{15-\frac{15}{11}+\frac{15}{121}}{16-\frac{16}{11}+\frac{16}{121}}\)
\(=\frac{5\left(1-\frac{1}{3}+\frac{1}{9}-\frac{1}{27}\right)}{8\left(1-\frac{1}{3}+\frac{1}{9}-\frac{1}{27}\right)}:\frac{15\left(1-\frac{1}{11}+\frac{1}{121}\right)}{16\left(1-\frac{1}{11}+\frac{1}{121}\right)}\)
\(=\frac{5}{8}:\frac{15}{16}\)
\(=\frac{2}{3}\)
a)\(\frac{5.27^3.4^5}{6^5}:\left(\frac{5^5.2^4}{10^4}.\frac{2^6.3^4}{6^4}\right)=\frac{5.\left(3^3\right)^3.\left(2^2\right)^5}{\left(2.3\right)^5}:\left(\frac{5^4.2^4.5}{10^4}.\frac{2^4.3^4.2^2}{6^4}\right)\)
\(=\frac{5.3^9.2^{10}}{2^5.3^5}:\left(\frac{10^4.5}{10^4}.\frac{6^4.4}{6^4}\right)=5.3^4.2^5:\left(5.4\right)=\frac{5.3^4.2^5}{5.2^2}=3^4.2^3=648\)
b) \(\frac{5-\frac{5}{3}-\frac{5}{9}-\frac{5}{27}}{8-\frac{8}{3}-\frac{8}{9}-\frac{8}{27}}=\frac{5\left(\frac{1}{3}-\frac{1}{9}-\frac{1}{27}\right)}{8\left(\frac{1}{3}-\frac{1}{9}-\frac{1}{27}\right)}=\frac{5}{8}\)
Phép tính còn lại bạn ghi rõ để mk làm tiếp
Sorry, thêm vào giữa 2 ps dấu : giúp mik nhé