1 x 2 x 4 x 8 x ... x 256 = ?
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a.\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)...\left(1-\frac{1}{2015}\right)=\frac{1}{2}.\frac{2}{3}...\frac{2014}{2015}=\frac{1.2.3...2014}{2.3...2015}=\frac{1}{2015}\)
b.\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{256}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+...+\frac{1}{128}-\frac{1}{256}=1-\frac{1}{256}=\frac{255}{256}\)
c.\(\frac{5}{2}+\frac{5}{4}+\frac{5}{8}+...+\frac{5}{256}=5\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{256}\right)=5.\frac{255}{256}=\frac{1275}{256}\)
d.14,35+(13,7-13,6).1=14,35+0,1.1=14,35+0,1=14,45
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Đặt biểu thức trên là A
Ta có :
A = 20 x 21 x 22 x ... x 28
=> A = 20 + 1 + 2 + ... + 8
=> A = 236
K nha bạn !!
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a) \(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+...+\dfrac{1}{256}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{8}+...-\dfrac{1}{128}+\dfrac{1}{128}-\dfrac{1}{256}\)
\(=1-\dfrac{1}{256}\)
\(=\dfrac{255}{256}\)
b) \(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{13.14}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{14}\)
\(=1-\dfrac{1}{14}\)
\(=\dfrac{13}{14}\)
c) \(\dfrac{3}{15.18}+\dfrac{3}{18.21}+\dfrac{3}{21.24}+...+\dfrac{3}{87.90}\)
\(=3.\left(\dfrac{1}{15.18}+\dfrac{1}{18.21}+\dfrac{1}{21.24}+...+\dfrac{1}{87.90}\right)\)
\(=3.\left[\dfrac{1}{3}.\left(\dfrac{1}{15}-\dfrac{1}{18}\right)+\dfrac{1}{3}.\left(\dfrac{1}{18}-\dfrac{1}{21}\right)+\dfrac{1}{3}.\left(\dfrac{1}{21}-\dfrac{1}{24}\right)+...+\dfrac{1}{3}.\left(\dfrac{1}{87}-\dfrac{1}{90}\right)\right]\)
\(=3.\dfrac{1}{3}.\left(\dfrac{1}{15}-\dfrac{1}{18}+\dfrac{1}{18}-\dfrac{1}{21}+\dfrac{1}{21}-\dfrac{1}{24}+...+\dfrac{1}{87}-\dfrac{1}{90}\right)\)
\(=\dfrac{1}{15}-\dfrac{1}{90}\)
\(=\dfrac{6}{90}-\dfrac{1}{90}\)
\(=\dfrac{5}{90}=\dfrac{1}{18}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
A= 1/2 + 1/4+ 1/8+ 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512 (1)
=> 2A=1+ 1/2 + 1/4+ 1/8+ 1/16 + 1/32 + 1/64 + 1/128 + 1/256 (2)
Lấy (1)-(2)
=> 2A-A=(1+ 1/2 + 1/4+ 1/8+ 1/16 + 1/32 + 1/64 + 1/128 + 1/256)-(1/2 + 1/4+ 1/8+ 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512)
=>A=1-1/512=511/512
5* nha bạn
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(x+4)+(x+8)+(x+12)+...+(x+32)=256
=>(x+x+x+......+x)+(4+8+12+.......+32)=256
mà số số hạng x tương ứng với số số hạng 4+8+12+...+32
=> có (32-4):4+1=8 số x
và tổng 4+8+12+.....+32=(32+4)x8:2=144
thay vào ta có :
8x X+144=256
=>8xX=112
=>X=14
![](https://rs.olm.vn/images/avt/0.png?1311)
Đặt \(A=25\times4-0,5\times40\times5\times0,2\times20\times0,25\)
\(\Leftrightarrow A=100-\left(0,5\times0,2\right)\times\left(40\times0,25\right)\times\left(5\times20\right)\)
\(\Leftrightarrow A=100-0,1\times10\times100\)
\(\Leftrightarrow A=100-100=0\)
Vậy theo đề bài, ta có :
\(\frac{25\times4-0,5\times40\times5\times0,2\times20\times0,25}{1+2+8+...+128+256}=\frac{0}{1+2+8+...+128+256}=0\)
Vậy ..................
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Đặt bểu thức là A
Ta có :
\(A=2^0.2^1.2^2.....2^8\)
\(\Rightarrow A=2^{0+1+2+3+...+8}\)
\(\Rightarrow A=2^{36}\)
1x2x4x8x16x...x256=20x21x22x23x...x28
=20+1+2+3+4+...+8
=236
vậy 1x2x4x8x..x256=236