Tính \(A=\frac{1,25.10:0,25.24,4.2}{6,1.2.6,25.4:0,25}+\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)...\left(1-\frac{1}{19}\right)\left(1-\frac{1}{20}\right)\)
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\(\frac{\left(1+17\right).\left(1+\frac{17}{2}\right).\left(1+\frac{17}{3}\right)...\left(1+\frac{17}{19}\right)}{\left(1+19\right).\left(1+\frac{19}{2}\right).\left(1+\frac{19}{3}\right)...\left(1+\frac{19}{17}\right)}\)
\(=\frac{18.\frac{19}{2}.\frac{20}{3}...\frac{36}{19}}{20.\frac{21}{2}.\frac{22}{3}...\frac{36}{17}}=\frac{18.19.20...36}{1.2.3...19}:\frac{20.21.22...36}{1.2.3...17}\)
\(=\frac{18.19.20...36}{1.2.3...19}.\frac{1.2.3...17}{20.21.22....36}=\frac{1.2.3...17.18...36}{1.2.3...19.20...36}=1\)
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\(M=\frac{18.\frac{19}{2}.\frac{20}{3}...\frac{36}{19}}{20.\frac{21}{2}.\frac{22}{3}...\frac{36}{17}}=\frac{\frac{18.19.20...36}{2.3...19}}{\frac{20.21.22...36}{2.3...17}}=\frac{\frac{18.19}{18.19}}{1}=\frac{1}{1}=1\)
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\(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)...........\left(1-\frac{1}{19}\right).\left(1-\frac{1}{20}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.............\frac{18}{19}.\frac{19}{20}\)
\(=\frac{1.2.3...........18.19}{2.3.4...................19.20}=\frac{1.\left(2.3.4..........18.19\right)}{\left(2.3.............19\right).20}=\frac{1}{20}\)
\(A=\frac{\left(1,25.10\right).4.24,4.2}{\left(6,1.2\right).\left(6,25.4\right).4}+\frac{1}{2}.\frac{2}{3}....\frac{18}{19}.\frac{19}{20}=\frac{12,5.4.24,4.2}{12,2.25.4}+\frac{1.\left(2.3..18.19\right)}{\left(2.3..18.19\right).20}=\frac{2.2}{2}+\frac{1}{20}=2+\frac{1}{20}=\frac{41}{20}\)