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3 tháng 2 2018

Đặt :

\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}\)

\(\Leftrightarrow\)\(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}+\frac{1}{2^5}+\frac{1}{2^6}+\frac{1}{2^7}\)

\(\Leftrightarrow\)\(2A=1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}+\frac{1}{2^5}+\frac{1}{2^6}\)

\(\Leftrightarrow\)\(2A-A=\left(1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^6}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^7}\right)\)

\(\Leftrightarrow\)\(A=1-\frac{1}{2^7}\)

Vậy \(A=1-\frac{1}{2^7}\)

9 tháng 8 2018

\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+...+\frac{1}{64}-\frac{1}{128}\)

\(=1-\frac{1}{128}\)

\(=\frac{127}{128}\)

6 tháng 7 2016

\(ĐặtA=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\)

\(2A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\)

\(2A-A=\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\right)\)

\(A=1-\frac{1}{64}=\frac{63}{64}\)

6 tháng 7 2016

= 32/64+16/64+8/64+4/64+2/64+1/64

=63/64

1 tháng 8 2015

Cách 1:

Đặt A = \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{128}\)

2A = \(1+\frac{1}{2}+\frac{1}{4}+....+\frac{1}{64}\)

A = 2A - A = \(1-\frac{1}{128}\)

=> A = \(\frac{127}{128}\)

Cách 2:

\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{128}\)

\(\left(1-\frac{1}{2}\right)+\left(\frac{1}{2}-\frac{1}{4}\right)+\left(\frac{1}{4}-\frac{1}{8}\right)+...+\left(\frac{1}{64}-\frac{1}{128}\right)\)

\(1-\frac{1}{128}\)

\(\frac{127}{128}\)

6 tháng 5 2017

1/2 - 1/4 + 1/4 - 1/8 + 1/8 - 1/16 + 1/16 - 1/32 + 1/32 - 1/64 + 1/64 - 1/128

Gạch 1/4 với 1/4 , 1/8 với 1/8 , 1/16 với 1/16 , 1/32 với 1/32 , 1/64 với 1/64

Còn 1/2 - 1/128 = 63/128 

Đúng thì k cho mình 

Dễ lắm bạn à : 

Đặt \(A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+....+\frac{1}{128}+\frac{1}{256}\)

 \(\Rightarrow2A=2\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+....+\frac{1}{128}+\frac{1}{256}\right)\)

\(\Leftrightarrow2A=2+1+\frac{1}{2}+\frac{1}{4}+....+\frac{1}{64}+\frac{1}{128}\)

\(\Leftrightarrow2A-A=2+1+\frac{1}{2}+\frac{1}{4}+....+\frac{1}{64}+\frac{1}{128}-\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+....+\frac{1}{128}+\frac{1}{256}\right)\)

\(\Leftrightarrow A=2-\frac{1}{256}=\frac{511}{256}\)

16 tháng 5 2018

đặt A= 1+1/2+1/4+1/8+...+1/128+1/256

2A=2+1+1/2+1/4+...+1/64+1/128

2A-A=A=2-1/256=511/256

5 tháng 6 2018

Theo đề bài ta có :

\(2B=1+\frac{1}{2}+\frac{1}{4}+...+\frac{1}{128}\)

\(\Leftrightarrow2B-B=\left(1+\frac{1}{2}+...+\frac{1}{128}\right)-\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{256}\right)\)

\(\Leftrightarrow B=1-\frac{1}{256}\)

\(\Leftrightarrow B=\frac{255}{256}\)

5 tháng 6 2018

\(B=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+..+\frac{1}{256}\)

\(\Rightarrow B=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+..+\frac{1}{2^8}\)

\(\Rightarrow2B=1+\frac{1}{2}+\frac{1}{2^2}+..+\frac{1}{2^7}\)

\(\Rightarrow2B-B=\left(1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^7}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^8}\right)\)

\(\Rightarrow B=1-\frac{1}{2^8}\)

5 tháng 8 2017

= 1 - 1/2+ 1/2- 1/4 +1/4 - 1/8 +1/8 -1/16 +1/16 -1/32 +1/32 -1/64 +1/64 - 1/128

= 1-1/128

=127/128

5 tháng 8 2017

\(\frac{1}{2}\)\(\frac{1}{4}\)\(\frac{1}{8}\)\(\frac{1}{16}\)\(\frac{1}{32}\)\(\frac{1}{64}\)\(\frac{1}{128}\)\(\frac{64}{128}\)\(\frac{32}{128}\)\(\frac{16}{128}\)\(\frac{8}{128}\)\(\frac{4}{128}\)\(\frac{2}{128}\)\(\frac{1}{128}\).

\(\frac{127}{128}\).

20 tháng 2 2018

\(\frac{1}{2}\)\(\frac{1}{4}\)\(\frac{1}{8}\)\(\frac{1}{16}\)\(\frac{1}{32}\)\(\frac{1}{64}\)\(\frac{1}{128}\)

\(1\)\(\frac{1}{2}\)\(\frac{1}{2}\)\(\frac{1}{4}\)\(\frac{1}{4}\)\(\frac{1}{8}\)\(\frac{1}{8}\)\(\frac{1}{16}\)\(\frac{1}{16}\)\(\frac{1}{32}\)\(\frac{1}{32}\)\(\frac{1}{64}\)\(\frac{1}{64}\)\(\frac{1}{128}\)

\(1\)\(\frac{1}{128}\)

\(\frac{127}{128}\)

28 tháng 6 2017

\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{256}\)

=\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+...+\frac{1}{128}-\frac{1}{256}\)

=\(1-\frac{1}{256}\)

=\(\frac{255}{256}\)

28 tháng 6 2017

1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256

= 128/256 + 64/256 + 32/256 + 16/256 + 8/256 + 4/256 + 2/128 + 1/256

= 255/256

5 tháng 8 2016

\(=1-\frac{1}{256}=\frac{255}{256}\)

5 tháng 8 2016

Nhận xét :

1/2 = 1 - 1/2   ;   1/4 = 1/2 - 1/4   ;   1/8 = 1/4 - 1/8   ;   .....   ;   1/256 = 1/128 - 1/256

=> A = 1 - 1/2 + 1/2 - 1/4 + 1/4 - 1/8 + ..... + 1/128 - 1/256

=> A = 1 - 1/256 = 255/256