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\(2x+3=8\)
\(\Rightarrow2x=8-3\)
\(\Rightarrow2x=5\)
\(\Rightarrow x=\dfrac{5}{2}\)
\(x:5-2=3\)
\(\Rightarrow x:5=3+2\)
\(\Rightarrow x:5=5\)
\(\Rightarrow x=5\cdot5\)
\(\Rightarrow x=25\)
\(x:7-2=19\)
\(\Rightarrow x:7=19+2\)
\(\Rightarrow x:7=21\)
\(\Rightarrow x=21\cdot7\)
\(\Rightarrow x=147\)
Mình chưa rõ đề
\(20-\left(x+3\right)=5\)
\(\Rightarrow-x-3=5-20\)
\(\Rightarrow-x-3=-15\)
\(\Rightarrow-x=-15+3\)
\(\Rightarrow-x=-12\)
\(\Rightarrow x=12\)
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a/\(450:\left(x-19\right)=50\)
=>\(x-19=9\)
=>\(x=28\)
Vậy...
b/\(3^2.\left(x+4\right)-5^2=5x.2^2\)
\(9\left(x+4\right)=20x+25\)
\(20x+25=9x-36\)
\(11x=-61\)
\(x=-\dfrac{61}{11}\)
Vậy..
c/Tương tự
d/Tương tự
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2.(x-3)-3.(x-1)=5-3.(x-2)+x+19
2x-6-3x+3=5-3x+6+x+19
-x-3=30-2x
-x+2x=3+30
x=33
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\(3^x+4^2=19^0.\left(19^3.19^2\right)-3.1^{2005}\)
\(3^x+16=1.19^5-3.1\)
\(3^x+16=2476099-3\)
\(3^x+16=2476096\)
\(3^x=2476096-16\)
\(3^x=2476080\)
\(3^x=2^4.3^2.5.19.181\)
\(\Rightarrow x\in\left\{\varnothing\right\}\)
Vậy,...
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a: =25(15+45*3)
=25*150
=3750
b: \(=-10\left(25+75-50\right)=-10\cdot50=-500\)
c: =>3^x-2=27
=>x-2=3
=>x=5
d: =>2x-5=-4
=>2x=1
=>x=1/2
e: =>2(x-1)^2=32
=>(x-1)^2=16
=>x-1=4 hoặc x-1=-4
=>x=-3 hoặc x=5
f: =>25(x+3)=75
=>x+3=3
=>x=0
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\(19^3+\left(2\cdot2\cdot2+2^3\right)\)
\(=19^3+8+8\)
\(=19^3+16=6875\)
19^3+(2×2×2+2^3)
=19^3+(2^3+2^3)
=6859+(8+8)
=6859+16
=6875